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Gnesinka [82]
3 years ago
7

What's the correct choice please help

Mathematics
1 answer:
nadezda [96]3 years ago
6 0

Answer:

$77,886

Step-by-step explanation:

We solve this question by proportions, using a rule of three.

The table states that:

$201.6 in 2006 is worth $232.957 in 2013.

We want to find:

The value of $90,000 in 2013 in 2006:

$201.6 - $232.957

x - $90000

Applying cross multiplication

232957x = 201.6*90000

x = \frac{201.6*90000}{232957}

x = 77886

$77,886 is the answer

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Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
The net below shows the dimensions of a triangular pyramid with equilateral base. The height of each triangle is 7.2 and the bas
Doss [256]

Answer:

25.98units³

Step-by-step explanation:

Area of the triangular prism = Base Area * Height of the pyramid

A = BH/3

Get the area of the triangle

Area of the triangle = 1/2 Base * height

Base of the triangle = 5

height = √5²-2.5²

h = √25-6.25

h = √18.75

h = 4.33

Area of the triangle = 1/2 * 4.33 * 5

Area of the triangle = 10.82

Base area = 10.82

Get the area of the triangular pyramid

Area of the triangular pyramid = 10.82*7.2/3

Area of the triangular pyramid = 25.98units³

Hence the area triangular pyramid is 25.98units³

6 0
2 years ago
James practiced piano for 48 minutes. Alisa practiced for 5 times as long as James. How many minutes did Alisa practice? How man
wariber [46]
48(5)=n 
when n= the amount of time that Alisa practiced the piano. 
Alisa practiced for 240 minutes.  

48+240= t
Where t stands for total minutes altogether.
In total, they practiced 288 minutes
7 0
3 years ago
A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks
Yakvenalex [24]

Answer:

The null hypothesis is, {H₀}: p = 0.66, H₀: p = 0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ​: p > 0.66

Step-by-step explanation:

Let p represent the proportion of students who are supportive of making the day before Thanksgiving a holiday.

Since two populations are considered, the alternative hypothesis for the difference of the means of the two populations has to be stated.

The proportion of two-third students are supportive of making the day before Thanksgiving a holiday is p = 0.66 obtained as shown below:

The null hypothesis is,

{H₀}:p = 0.66, H₀​: p = 0.66

The alternative hypothesis is,

{Hₐ:p > 0.66, Ha​: p > 0.66

The null hypothesis is, {H₀}: p = 0.66, H₀: p=0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ​: p > 0.66

3 0
3 years ago
Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i
steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given  Z₁ = 9 - 9 i    and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A =  Z₁ = x₁ +i y₁ = 9 - 9 i and

    B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

     (x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

    A B   =   \sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2}    }

    A B =   \sqrt{(10 - 1)^{2}+(-9 - (-9))^{2}    }

   AB   = \sqrt{(9)^{2} +(-9+9)^{2} }

 <em> AB    =  √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

3 0
3 years ago
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