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fredd [130]
3 years ago
15

A woman pushes a 27 kg lawnmower at a steady speed. She exerts a 120 N force in a direction 35◦ below the horizontal. The accele

ration of gravity is 9.8 m/ 2 . 27 kg 120 N 35◦ Find the magnitude of the vertical force this lawnmower exerts on the lawn. Answer in units of N.
Physics
1 answer:
nikklg [1K]3 years ago
3 0

The vertical force exerted on the lawn is 68.8 N downward

Explanation:

The vertical force exerted by the lawnmower on the lawn is equal to the vertical component of the force applied, therefore:

F_y = F sin \theta

where

F is the magnitude of the force applied

\theta is the angle between the direction of the force and the horizontal

In this problem:

F = 120 N

\theta=-35^{\circ}

Substituting,

F_y = (120)(sin 30)=-68.8 N

where the negative sign means the direction of the force is downward.

Learn more about vector components and forces here:

brainly.com/question/2678571

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string traces out a cone (see fi
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a

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The diagram illustrating this is shown on the first uploaded

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     The angle made  by the string is  \theta  =  5.58^o

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Now From the diagram we see that this force is equivalent to

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Now the downward normal force acting on the bob is  mathematically represented as

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So

       \frac{Tsin \ttheta }{Tcos \theta }  =  \frac{\frac{mv^2}{r} }{mg}

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=>   g tan \theta  = \frac{v^2}{r}

The centripetal acceleration which the same as the radial acceleration  of the bob is mathematically represented as

      a_c  =  \frac{v^2}{r}

=>  a_c  = gtan \theta

substituting values

     a_c  =  9.8  *  tan (5.58)

     a_c  = 0.9574 m/s^2

The horizontal component is mathematically represented as

     T_x  = Tsin \theta = ma_c

substituting value

   T_x  = 0.344 *  0.9574

    T_x  = 0.3294 \ N

The vertical component of  tension is  

    T_y  =  T \ cos \theta  = mg

substituting value

     T_ y  =  0.344 * 9.8

      T_ y  = 3.2712 \ N

The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is  

         

       T  = T_x i  + T_y  j

substituting value  

      T  = [(0.3294) i  + (3.3712)j ] \  N

         

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