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3 years ago

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A woman pushes a 27 kg lawnmower at a steady speed. She exerts a 120 N force in a direction 35◦ below the horizontal. The accele

ration of gravity is 9.8 m/ 2 . 27 kg 120 N 35◦ Find the magnitude of the vertical force this lawnmower exerts on the lawn. Answer in units of N.

1 answer:

nikklg [1K]3 years ago

3 0

The vertical force exerted on the lawn is 68.8 N downward

Explanation:

The vertical force exerted by the lawnmower on the lawn is equal to the vertical component of the force applied, therefore:

$F_y = F sin \theta$

where

F is the magnitude of the force applied

$\theta$ is the angle between the direction of the force and the horizontal

In this problem:

F = 120 N

$\theta=-35^{\circ}$

Substituting,

$F_y = (120)(sin 30)=-68.8 N$

where the negative sign means the direction of the force is downward.

Learn more about vector components and forces here:

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2 years ago

Pete Zaria works on weekends at Barnaby's Pizza Parlor. His primary responsibility is to fill drink orders for customers. He fil

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Answer:

$W_n_e_t=7.648512 \approx 7.6J$

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Explanation:

From the question we are told that

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Force on pitcher $f=8.8N$

Distance traveled $48cm=>0.48m$

Coefficient of friction $\mu=0.28$

a)Generally frictional force is mathematically given by

$F=\mu N$

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Generally work done on the pitcher is mathematically given as

$W_n_e_t=W_f+W_F$

$W_f=8.8*0.48=>4.224N\\W_F=7.1344*0.48=>3.424512N$

$W_n_e_t=4.224-3.424512$

$W_n_e_t=0.799488\approx 0.8J$

b)Generally K.E can be given mathematically as

$K.E= W_n_e_t$

Therefore

$K.E=0.8J$

c)Generally the equation for kinetic energy is mathematically represented by

$K.E=1/2mv^2$

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Velocity as subject

$v=\sqrt{\frac{K.E*2}{m} }$

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Explanation:

Given that,

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Where, V = terminal voltage

I = current

r = internal resistance

Put the value into the formula

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$V=3.18\ V$

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2 years ago

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Answer:

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1 nm = 10⁻³ nm

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3 years ago

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