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Bess [88]
4 years ago
7

Quiz Active 1 2 3 4 5 6 7 8 10 TIME REMAINING 52:33 Which conclusion is best supported by the information? Rhea kicks a soccer b

all at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference trame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h. Sean is standing still, and Rhea is running toward Sean while kicking the ball. O Rhea is standing still after kicking the ball, and Sean is running away from Rhea. Both soccer players are standing still after the ball is kicked Both soccer players are running while the ball is in moton.​
Physics
1 answer:
omeli [17]4 years ago
4 0

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Explanation:

The conclusion that is best supported by the information is the fact that Sean is standing still, and Rhea is running toward Sean while kicking the ball. This answer is chosen because from the question it is stated that Rhea kicks the ball to Sean and the velocity of the ball is faster from Sean's point of reference. This is only possible if Rhea was already in motion, as his own speed would have been countered by the speed of the ball in itself. Thereby making the speed of the ball slower from his point of his reference

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While in sketch mode, the number displayed to the right of the cursor defines the sketch element`s exact size. Therefore, there
galina1969 [7]

Answer:

B) False.

Explanation:

Most of the times, the numbers that appears right to the cursor are representing the coordinates (x & y) of the cursor. So as the cursor moves around the screen those number changes accordingly.Therefore its wrong to say that there is no need to add a dimension to set the dimensional value.

7 0
3 years ago
Pascal in term fundamental unit is? ​
Aleksandr-060686 [28]

Answer: SI unit of pressure

Explanation: The pascal (pronounced pass-KAL and abbreviated Pa) is the unit of pressure or stress in the International System of Units (SI). Reduced to base units in SI, one pascal is one kilogram per meter per second squared; that is, 1 Pa = 1 kg · m-1 · s-2.

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8 0
3 years ago
The rate of cooling determines ....... and ......​
PilotLPTM [1.2K]

Answer:

freezing point and melting point

7 0
3 years ago
The SI unit of average spped and velocity.​
Verdich [7]

<em>meter per</em><em> </em><em>second</em><em> </em><em>is </em><em>the </em><em>main </em><em>answer </em><em>of</em><em> </em><em>both</em>

3 0
3 years ago
A thin rod of length 0.75 m and mass 0.42 kg is suspended
MrRissso [65]

Answer:

a)  K = 0.63 J, b)  h = 0.153 m

Explanation:

a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is

         w² = \frac{m g d}{I}

where d is the distance from the pivot point to the center of mass and I is the moment of inertia.

The rod is a homogeneous body so its center of mass is at the geometric center of the rod.

              d = L / 2

the moment of inertia of the rod is the moment of a rod supported at one end

              I = ⅓ m L²

we substitute

            w = \sqrt{\frac{mgL}{2}  \ \frac{1}{\frac{1}{3} mL^2} }

            w = \sqrt{\frac{3}{2}  \ \frac{g}{L} }

            w = \sqrt{ \frac{3}{2} \ \frac{9.8}{0.75}  }

            w = 4.427 rad / s

an oscillatory system is described by the expression

              θ = θ₀ cos (wt + Φ)

the angular velocity is

             w = dθ /dt

             w = - θ₀ w sin (wt + Ф)

In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1

In the exercise it is indicated that at the lowest point the angular velocity is

           w = 4.0 rad / s

the kinetic energy is

           K = ½ I w²

           K = ½ (⅓ m L²) w²

           K = 1/6 m L² w²

           K = 1/6 0.42 0.75² 4.0²

           K = 0.63 J

b) for this part let's use conservation of energy

starting point. Lowest point

             Em₀ = K = ½ I w²

final point. Highest point

             Em_f = U = m g h

energy is conserved

             Em₀ = Em_f

             ½ I w² = m g h

             ½ (⅓ m L²) w² = m g h

             h = 1/6 L² w² / g

             h = 1/6 0.75² 4.0² / 9.8

             h = 0.153 m

5 0
3 years ago
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