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3 years ago

Maceo is making rock candy. Which best describes the steps she should take?

Physics

2 answers:

Ymorist [56]3 years ago

4 0

Answer:

<h2>Heat a saturated sugar water solution, dissolve more sugar, then let the solution cool</h2>

Explanation:

To make rock candy, you first need to place the water in a pan and bring it to boil. At the beginning you make a sugar water solution by adding a bit of sugar, that will ensure that you have the right temperature (remember, the more sugar you add, the harder is to dissolve it).

After you do the first process, then you continue to add the rest of the sugar while you stir, when it's completely dissolved, you remove the pan from the heat, and let the solution cool.

Therefore, the right answer is the first choice, because describes best the process.

Andru [333]3 years ago

3 0

Answer:

The answer is heat a saturated sugar water solution, dissolve more sugar, then let the solution cool

Explanation:

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Speed (ex: meters/second, miles/hour)

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An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple har

sineoko [7]

Answer:

Acceleration will be equal to $2m/sec^2$

Explanation:

We have given mass of the object m = 0.4 kg

Spring constant k = 8 N/m

Maximum displacement of the spring is given x = 0.1 m

From newton's law force is equal to $F=ma$ .....eqn 1

By hook's law spring force is equal to $F=kx$ .....eqn 2

From equation 1 and equation 2

$ma=kx$

$0.4\times a=8\times 0.1$

$a=2m/sec^2$

So acceleration will be equal to $2m/sec^2$

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3 years ago

A simple pendulum has a period of 2.5 s. What is its period if its length is increased by a factor of four?

Svetach [21]

Answer:

Its period if its length is increased by a factor of four is 5 s.

Explanation:

The period of a simple pendulum is given by;

$T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi} = \sqrt{\frac{l}{g} } \\\\ \frac{T^2}{4\pi^2} = \frac{l}{g}\\\\\frac{T^2}{l} = \frac{4\pi^2}{g} \\\\let \ \frac{4\pi^2}{g} \ be \ constant \\\\\frac{T_1^2}{l_1} = \frac{T_2^2}{l_2} \\\\$

Given;

initial period, T₁ = 2.5

initial length, = L₁

new length, L₂ = 4L₁

the new period, T₂ = ?

$\frac{T_1^2}{l_1} = \frac{T_2^2}{l_2} \\\\T_2^2 = \frac{T_1^2 l_2}{l_1} \\\\T_2 = \sqrt{\frac{T_1^2 l_2}{l_1}} \\\\ T_2 = \sqrt{\frac{(2.5)^2 \ \times \ 4l_1}{l_1}}\\\\ T_2 =\sqrt{(2.5)^2 \ \times \ 4}\\\\T_2 = \sqrt{25} \\\\T_2 = 5\ s$