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Leno4ka [110]
2 years ago
9

A 1,811 kg car goes over the top of a hill of radius 20 m. What is the maximum speed the car can

Physics
1 answer:
mezya [45]2 years ago
8 0
If I had an answer to the question, I would tell you but I dont. I’m just doing this because I have to for free answers. And it has to be 20 characters long.
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The energy required to completely remove the covalent bond between two
hoa [83]

Answer:

B is the answer. Correct me if I'm wrong

7 0
3 years ago
A spy camera is said to be able to read the numbers on a car's license plate. If the numbers on the plate are 4.30 cm apart, and
Maslowich

Answer:

D = 2.38 m

Explanation:

This exercise is a diffraction problem where we must be able to separate the license plate numbers, so we must use a criterion to know when two light sources are separated, let's use the Rayleigh criterion, according to this criterion two light sources are separated if The maximum diffraction of a point coincides with the first minimum of the second point, so we can use the diffraction equation for a slit

         a sin θ  = m λ

Where the first minimum occurs for m = 1, as in these experiments the angle is very small, we can approximate the sine to the angle

           θ = λ / a

Also when we use a circular aperture instead of slits, we must use polar coordinates, which introduce a numerical constant

           θ = 1.22 λ / D

Where D is the circular tightness

       

Let's apply this equation to our case

         D = 1.22 λ /  θ

To calculate the angles let's use trigonometry

         tan  θ = y / x

          θ = tan⁻¹  y / x

          θ = tan⁻¹ (4.30 10⁻² / 140 10³)

          θ = tan⁻¹ (3.07 10⁻⁷)

          θ = 3.07 10⁻⁷ rad

Let's calculate

        D = 1.22 600 10⁻⁹ / 3.07 10⁻⁷

        D = 2.38 m

4 0
3 years ago
Read 2 more answers
A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the
Alex17521 [72]

Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3  m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1       V = 1.50*10^-3  m^3       ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J

W = 3.12 J

Hope this helps!

4 0
3 years ago
Which statement is correct? When a positively charged atom looses an electron to a positively charged atom, two neutral atoms ar
vazorg [7]
I believe the answer is "When a neutral atom looses an electron to another neutral atom, two charged atoms are created."
3 0
2 years ago
Read 2 more answers
Hooke’s law describes the linear relationship between stress and strain through Young’s modulus. Given two materials under the s
stiks02 [169]

Answer:

The material with higher modulus will stretch less than

The material with lower modulus

Explanation:

A material with a higher modulus is stiffer and has better resistance to deformation. The modulus is defined as the force per unit area required to produce a deformation or in other words the ratio of stress to strain.

E= stress/stain

Hooks law states that provided the elastic limit is not exceeded the extension e of a spring is directly proportional to the load or force attached

F=ke

Where k is the constant which gives the measure of the spring under tension

3 0
3 years ago
Read 2 more answers
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