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3 years ago

Someone help me with this question

Mathematics

1 answer:

Savatey [412]3 years ago

5 0

It’s b because the number 8 on top of the fraction’s an exponent meaning that u times the amount of number 8 times but for both of the numerator and denominator

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Describe how you regroup when you find the sum of 64 + 43

Leno4ka [110]

All i do is i think of 4+3 which equals 7 and then 6+4 which equals 10 then i put the numbers together.

so my answer is 107

64
43
----------------
107

4 0

3 years ago

Read 2 more answers

The median household incomes in dollars in four towns over time are shown. Assume the median incomes increase linearly. Median H

marysya [2.9K]

Answer:

Step-by-step explanation:

Household. Year 2010. Year 2015. Difference

Adderley. 47,200 58,200. 11,000

Bonniville. 52,900. 62,400. 9,500

Clay City. 44,600. 57,600. 13,000

Daletown. 41,500. 54,000. 12,500

Percentage increase for Adderley = 11,000/47,200 * 100= 23.3%

Percentage increase for Bonniville = 9,500/52,900 * 100= 17.96%

Percentage increase for Clay City = 13,000/44,600 * 100= 29.15%

Percentage increase for Daletown = 12,500/41,500 * 100= 30.12%

We can now see that Bonniville is the city with the lowest rate of increase in median household income.

7 0

3 years ago

Simplify each radical expression

nlexa [21]

31.
$5 \sqrt{6} - 3 \sqrt{6} = 2 \sqrt{6}$
32.
$\sqrt{2} ( \sqrt{8} + \sqrt{6} ) \\ \sqrt{16} + \sqrt{12} \\ 4 + 2 \sqrt{3}$
33.
$(3 \sqrt{2} - 2 \sqrt{5} )(4 \sqrt{2} + 2 \sqrt{5} ) \\ 12 \sqrt{4} + 6 \sqrt{10} - 8 \sqrt{10} - 4 \sqrt{25} \\ 24 - 2 \sqrt{10} - 20 \\ 4 - 2 \sqrt{10}$
pls mark me as brainliest

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3 years ago

Tyler wants to buy a new television that costs $312. He has already saved $96. He plans to save $24 per week over the next few w

Elena L [17]

Answer:

Step-by-step explanation:

5 0

2 years ago

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Write the definition of a function minmax that has five parameters. the first three parameters are integers. the last two are se

Nitella [24]

Hello,

function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};

if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};

// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);

8 0

3 years ago