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adelina 88 [10]
3 years ago
7

What is the difference between a compound and a mixture?

Chemistry
1 answer:
nataly862011 [7]3 years ago
7 0
In order: B, D, A, A, A. C, A
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What is the decreasing order of atomic size<br>F, Mg, Sr, P​
lesya692 [45]

Answer:

Sr, Mg, P, F

Explanation:

The trend for decreasing radii size is up and to the right of the Periodic Table.

4 0
3 years ago
State one similarity in the electronic structure between sodium and chlorine?
Anna71 [15]
I think the answer is that they both don’t have a full outer shell

i hope this helps
8 0
3 years ago
When chlorine and magnesium react chemically, how many chlorine atoms will combine with one magnesium atom?
Lesechka [4]
Magnesium is divalent. This means that one magnesium atom needs to lose 2 electrons in order to become stable.

Chlorine, on the other hand, is monovalent. This means that one chlorine atom needs to gain one electron in order to become stable.

Based on this, one magnesium atom will combine with two chlorine atoms, where the magnesium loses two electrons, one for each chlorine.

The formula of the compound formed is: MgCl2
8 0
3 years ago
What is the minimum amount of 6.9 M H2SO4 necessary to produce 27.8 g of H2 (g) according to the following reaction? 2Al(s)+3H2S
Arte-miy333 [17]

Answer : The minimum amount of 6.9 M H_2SO_4 needed is, 2.0 L

Explanation :

The given chemical reaction is:

2Al(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2(g)

First we have to calculate the moles of H_2

\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}

Molar mass of H_2 = 2 g/mol

\text{Moles of }H_2=\frac{27.8g}{2g/mol}=13.9mol

Now we have to calculate the moles of H_2SO_4

From the balanced chemical reaction we conclude that,

As, 3 moles of H_2 produced from 3 moles of H_2SO_4

So, 13.9 moles of H_2 produced from 13.9 moles of H_2SO_4

Now we have to calculate the mass of H_2SO_4

\text{Concentration of }H_2SO_4=\frac{\text{Moles of }H_2SO_4}{\text{Volume of }H_2SO_4}

6.9M=\frac{13.9mol}{\text{Volume of }H_2SO_4}

\text{Volume of }H_2SO_4=2.0L

Thus, the minimum amount of 6.9 M H_2SO_4 needed is, 2.0 L

3 0
4 years ago
When zinc (or aluminum) was allowed to react with the copper sulfate what was the limiting reagent?
PtichkaEL [24]
CuSO₄ or Copper Sulfate will be the limiting reagent when the zinc or aluminum was allowed to react with the copper sulfate. Copper Sulfate with the chemical symbol <span>CuSO₄ also known as cupric sulfate or copper sulphate, is used for fungicide. </span>
8 0
3 years ago
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