Answer: B. An experiment that directly tests the hypothesis
Explanation:
Yasir didn’t really test his experiment he only ask people for the opinion on which color they like so he forget to actually do the experiment therefore the answer is b.
Answer:
I honestly dont know but its cool problably from water fill or from the waves going to much
Explanation:
194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.
Explanation:
In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.
It is known that 1 moles of any element has 6.022×10²³ molecules.
Then 1 molecule will have
moles.
So 
Thus, 1.66 moles are included in BCl₃.
Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.
As it is known as 1 mole contains molecular mass of the compound.
As the molecular mass of BCl₃ will be

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.
Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.


So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.
Balanced chemical equation for the hydrogenation of glyceryl trilinolenate:
C₅₇H₉₂O₆ + 9H₂ → C₅₇H₁₁₀O₆.
Linolenic acid (octadecatrienoic acids ) is a type of fatty acid. It has 18 carbon atoms chain and three double bonds. So trilinolenate has nine double bonds.
Trilinolenate is the form of triglyceride esters of linolenic acid.
Hydrogenation is addition of hydrogen atoms at both sides of a double bond.
Answer:
d.-379 cal/mol
Explanation:
ΔG = ΔG⁰ + RT ln K
for equilibrium ΔG = 0
ΔG⁰ + RT ln K =0
ΔG⁰ = - RT ln K
PG ⇒ PEP
K = [ PEP ] / [ PG ]
= .68 / .32
= 2.125
ΔG⁰ = - 1.987 x 273 x ln 2.125
= - 409 Cal / mole
Option d is the nearest answer .