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Darya [45]
3 years ago
13

How to find the average atomic mass

Chemistry
1 answer:
Grace [21]3 years ago
6 0
The chlorine isotope with 18 neutrons has an abundance of 0.7577 and a mass<span> number of 35 amu. To </span>calculate<span> the </span>average atomic mass<span>, multiply the fraction by the </span>mass<span> number for each isotope, then add them together.
hope this help</span>
You might be interested in
The question is below
rodikova [14]
The anode is the electrode where the oxidation occurs.

Cathode is the electrode where the reducction occurs.

Equations:

  Mn(2+) + 2e-  --->  Mn(s)                      Eo = - 1.18 V
2Fe(3+) + 2e-  ----> 2 Fe(2+)                2Eo = + 1.54 V

The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.

Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72

Answer: 2.72 V

3 0
3 years ago
Consider the following reaction.
Ivan

Answer:

162 g Fe₂O₃

Explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

18.3 g C           1 mole            2 moles Fe₂O₃          159.684 g
--------------  x  ----------------  x  -------------------------  x  -----------------  = 162 g Fe₂O₃
                        12.011 g              3 moles C                 1 mole

5 0
2 years ago
If the percent by volume is 2.0% and the volume of solution is 250 mL, what is the volume of solute in solution? Show your work.
Mrrafil [7]
Volume of solute = 250 * 2%
= 250 * 0.02
= 5

In short, Your Answer would be 5 mL

Hope this helps!
3 0
3 years ago
What did Ernest Rutherford’s gold foil experiment demonstrate about atoms ?
Alchen [17]

Answer:

Their positive charge is located in the small nucleus

Explanation:

Ernest Rutherford performed the gold foil experiment in 1911 where he used alpha particles generated from a radioactive source to bombard a thin gold foil.

In his experiment, he observed that the bulk of the alpha particles passed through the gold foil, just a tiny fraction was deflected back. To explain his findings, Rutherford proposed that an atom is made of positively charged centre where nearly all the mass is concentrated called nucleus. Surrounding the nucleus is a large space containing electrons.

4 0
3 years ago
Read 2 more answers
Please help!! 20 points!! Posted this previously and forgot to change it to 20 points but it is now
spayn [35]

Answer:

0.571 mol

Explanation:

Given data:

Number of moles of NaHCO₃ = 0.571 mol

Number of moles of CO₂ produced = ?

Solution:

Chemical equation:

NaHCO₃ + C₃H₆O₃   →     CO₂  + C₃H₅NaO₃ + H₂O

Now we will compare the moles of CO₂ with NaHCO₃ from balance chemical equation.

                             NaHCO₃          :            CO₂

                                    1                :               1

                                 0.571            :            0.571

So number of moles of CO₂  produced are 0.571.

3 0
3 years ago
Read 2 more answers
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