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3 years ago

What is the decreasing order of atomic sizeF, Mg, Sr, P

Chemistry

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

Sr, Mg, P, F

Explanation:

The trend for decreasing radii size is up and to the right of the Periodic Table.

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____ is an important nutrient for pregnant mothers.

Elanso [62]

Its all of the above.

- I took the test and mine is correct.

3 0

3 years ago

A sample of gas is inside of a rigid container with fixed volume of 350mL. The initial pressure of the system is 366kPa, and the

Cerrena [4.2K]

Answer:

457.5kPa

Explanation:

Given data

V1=V2=350mL (<em>fixed volume</em> )

P1=366kPa

T1= 88 degrees Celsius

P2=??

T2= 110 degrees Celsius

For the general gas equation

P1V1/T1= P2V2/T2

V1=V2

P1/T1= P2/T2

Substitute

366/88= P2/110

Cross multiply we have

P2*88=366*110

P2*88= 40260

P2= 40260/88

P2= 457.5 kPa

Hence the pressure will change to 457.5kPa

3 0

3 years ago

When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C

natka813 [3]

Answer:

$\Delta_{r}U$ of the reaction is -6313 kJ/mol

$\Delta_{r}H$ of the reaction is -6312 kJ/mol

Explanation:

$Temperature\,\,change= \Delta U = 29.419-25.823 =3.506^{o}C$

$q_{cal}= C \times \Delta T$

$=5.861 \times 3.596 = 21.076\,kJ$

$q_{rxn}= -q_{cal}= -21.076\,kJ$

$\Delta_{r}U= -21.076 \times \frac{154}{0.5141}= -6313\, kJ/mol$

Therefore, $\Delta_{r}U$ of the reaction is -6313 kJ/mol.

The chemical reaction in bomb calorimeter is as follows.

$C_{12}H_{10}(s)+\frac{27}{2}O_{2}(g)\rightarrow 12CO_{2}(g)+5H_{2}O(g)$

$Number\,of\,moles\Delta n=(12+5)-\frac{27}{2}=3.5$

$\Delta_{r}H=\Delta E+ \Delta n. RT$

$=-6313+3.5\times 8.314\times 10^{-3} \times 3.596=-6312\,kJ/mol$

Therefore, $\Delta_{r}H$ of the reaction is -6312 kJ/mol.

3 0

3 years ago

How many joules of heat are needed to raise the temperature of 47.5 g of aluminum from 21°C to 94°C , if the specific heat of al

Montano1993 [528]

Answer:

3120.75J

Explanation:

So, we have the formula $q = mc\Delta t$ . For this example, q is the heat energy in Joules, m is the mass in grams, c is the specific heat capacity in $\frac{J}{{g\°C}}$ , and $\Delta$ t is the change in temperature. In this case, m = 47.5g, c = 0.9 $\frac{J}{{g\°C}}$ , and $\Delta$ t = 94-21 = 73°C. Plugging in the values, we get the joules of heat required to raise 47.5g of Al from 21°C to 94°C which is stated above. You can double check my answer but that should be it. An important thing to be aware of are the units. Sometimes, the heat capacity may not be $\frac{J}{{g\°C}}$ . I may be in Kelvin or something. Anyways, hope this helps.

5 0

4 years ago

2 Which best describes an acid?

tester [92]

D. A sour liquid that forms gas bubblee when mixed with copper

7 0

3 years ago

What is the decreasing order of atomic sizeF, Mg, Sr, P​

What is the decreasing order of atomic sizeF, Mg, Sr, P