The reaction corresponds to the combustion of propane (C3H8). The balanced reaction is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
The reaction enthalpy is given as:
ΔHrxn = ∑nΔH°f(products) - ∑ nΔH°f(reactants)
= [3ΔH°f(CO2(g)) + 4ΔH°f(H2O(g)] - [1ΔH°f(C3H8(g)) + 5ΔH°f(O2(g)]
= [3(-393.5) + 4(-241.8)] - [-103.9 + 5(0)] = -2043.8 kJ
The enthalpy for the combustion of propane is -2044 kJ
Answer:
The answer to your question is 71.22 g
Explanation:
Data
Density = 19.3 g/cm³
Volume = 0.00369
mass = ?
Formula
Density = 
Solve for mass
mass = density x volume
Process
1.- Convert volume from liters to cubic centimeters
1 l ---------------- 1000 cm³
0.00369l --------- x
x = (0.00369 x 1000 ) / 1
x = 3.69 cm³
2.- Substitution
mass = 19.3 x 3.69
3.- Simplification and result
mass = 71.22 g
I really don’t know. Sorry
<span>For 1 mole of MgCl2, it would require 2 moles of KOH. ( 1 : 2 mole ratio)
Since you have 3 moles of KOH, it is in excess, and MgCl2 is the limiting reactant.</span><span>
</span>
Answer:
Helium is lighter than Hydrogen and Helium is a much safer gas.