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NeTakaya
2 years ago
11

How many unique triangles can be drawn with side lengths 8 in., 12 in., and 24 in.? Explain

Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

By using the triangular inequality, we will see that no triangles can be made with these side lengths.

<h3>How many triangles can be made with these side lengths?</h3>

Remember that for any triangle with side lengths A, B, and C, the triangular inequality must be true.

This means that the sum of any two sides must be larger than the other side.

A + B > C

A + C > B

B + C > A.

For the given side lengths, we will have:

8 in + 12 in > 24 in

8in + 24 in > 12 in

12 in + 24 in > 8 in.

Now, notice that the first inequality is false. So the triangular inequality is not meet. Then we can't make a triangle with these side lengths.

So we can make 0 unique triangles with these side lengths.

If you want to learn more about triangles:

brainly.com/question/2217700

#SPJ1

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sergeinik [125]

Step-by-step explanation:

perimeter=28

length=2x

width=x

28=2(x+2x)

28=2x+4x

28=6x

28/6=6x/6

4.67=x

width=4.67

length=2×4.67

=9.34

4 0
3 years ago
A straight line has equation 3y-3x=4. Write down the equation of another straight line parallel to it
Sophie [7]
Y = 3x + 4/3
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3 years ago
On a particular day, the wind added 5 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 5 miles pe
olga55 [171]

Answer:

45

Step-by-step explanation:

The first part of the question is to throw you off and is of no use

To find the answer you must find the midpoint of 30 and 60

which shall give you 45 and that is the answer to the question

Hope this helped you

3 0
3 years ago
At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0
2 years ago
Make P the subject.<br> Q = 3P + 2
Ne4ueva [31]

Answer:

P = \frac{Q-2}{3}

Step-by-step explanation:

Q = 3P + 2 ( subtract 2 from both sides )

Q - 2 = 3P ( isolate P by dividing both sides by 3 )

\frac{Q-2}{3} = P

4 0
2 years ago
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