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Luden [163]
4 years ago
11

I need help with know number 5 and 6 can anyone help me

Mathematics
1 answer:
LenaWriter [7]4 years ago
3 0
Give me a min i need to think but ill get back to you as soon as possible
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How many solutions does the following system of linear equations have?
Mademuasel [1]
2 this is right because 6 +1 and 6x 5x
3 0
3 years ago
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
4 years ago
A pack of pencils contain a dozen pencils.450 such packs were put in a carton. If there are 25 such cartons, find the total numb
Serhud [2]

Answer:

135000

Step-by-step explanation:

Given: A pack of pencils contain a dozen pencils. 450 such packs were put in a carton. There are 25 such cartons.

To find: total number of pencils

Solution:

Total number of pencils in a pack = 1 dozen = 12

Total number of packs = 450

Total number of cartons = 25

Total number of pencils = 12 × 450 × 25 = 135000

So, total number of pencils is 135000.

4 0
3 years ago
Write each binomial square as a trinomial. <img src="https://tex.z-dn.net/?f=%28x-6%29%5E2" id="TexFormula1" title="(x-6)^2" alt
bogdanovich [222]
The answer is: X^2 - 12x + 36 hope that helps
7 0
3 years ago
Find the measure of the indicated angle. Need help please.<br> I need explanation <br><br> THANK YOU
Nonamiya [84]

Answer: Approximately 28 km

The more accurate, yet still approximate value, is roughly 27.995735464379

Round that however you need to.

=============================================================

Explanation:

As the diagram shows, the uppercase letters A,B,C represent the corner points of the triangle. They also represent the angles. The diagram says that:

  • angle A = 59
  • angle B = 91

The missing angle C is....

A+B+C = 180

C = 180-A-B

C = 180-59-91

C = 30

which we'll use later.

Convention usually has the side lengths be lowercase letters 'a', b, and c. Those lowercase letters are opposite their uppercase counterpart. We'll have side 'a' opposite angle A, then b is opposite B, and c is opposite C. This allows us to quickly label a triangle and find the missing sides and/or angles. The phrasing "solve the triangle" basically means "find all the missing sides and angles". For this problem, we're only concerned with one side.

The diagram says that side c = 14 due to it being opposite angle C.

The goal is to find side b, which is the shorter way of saying "find AC".

-------------------------

From here, we can use the law of sines to find side b

b/sin(B) = c/sin(C)

b/sin(91) = 14/sin(30)

b = sin(91)*14/sin(30)

b = 27.995735464379 which is approximate

b = 28

Side AC is roughly 28 km long.

I rounded to the nearest whole number since the "14 km" is also a whole number. Your teacher may want you to round differently.

Make sure your calculator is in degree mode.

7 0
3 years ago
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