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Oduvanchick [21]
3 years ago
10

In a 24 km race, during which each runner maintains a constant speed throughout, Alice crosses the finish line while Becky is st

ill 8 km from finishing and Caitlin is 12 km from finishing. When Becky crosses the finish line, Caitlin still has $d$ kilometers to go. Find all possible values of $d$.
Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
12/16=3/4, 3/4*8=6. Therefore Caitlin still has 6 km to go, So d=6

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Answer CORRECTLY !!!!! Will mark brainliest !!!!
mash [69]

Answer:

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Step-by-step explanation:

Given

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Rearrange making r the subject

Add 7q to both sides

12r = 10q - 4r ( add 4r to both sides )

16r = 10q ( divide both sides by 16 )

r = \frac{10q}{16} = \frac{5q}{8} , thus

g(q) = \frac{5q}{8}

4 0
3 years ago
Read 2 more answers
Please answer correctly
Phoenix [80]

Answer:

26

Step-by-step explanation:

18 - 2^4 * (-0.5)

Calculate 2 to the power of 4 and get 16.

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Multiply 16 and −0.5 to get −8.

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The opposite of −8 is 8.

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2 years ago
How would I simplify the equation 5u^6x^2+20wx/15x^4
Akimi4 [234]

Answer:

The simplified form is 5u^6x^2+\frac{4w x^{-3}}{3}

Step-by-step explanation:

To simplify the expression given to use, we need to reduce the given expression in its simplest form. There should not be any possibility for the further cancelling out of the division terms, if any.

Now the expression that is given to us is:

5u^6x^2+\frac{20wx}{15x^4}\\

Here we will simplify it, as follows:

5u^6x^2+\frac{20wx}{15x^4}\\=5u^6x^2+\frac{4w}{3x^3}\\=5u^6x^2+\frac{4w x^{-3}}{3}

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3 0
3 years ago
What is the LCM of x^2+5 and x^2+10x+25?
avanturin [10]

Answer:

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Step-by-step explanation:

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On factorising we have:

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= x(x+5) +5(x+5

= (x+5)(x+5)

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The LCM can be calculated as thus

| x²+5, (x+5)²

x+5| x²+5, (x+5)

x+5| x²+5, 1

x²+5| 1, 1

The factors of both equation are x+5 × x+5 × x²+5

The LCM will be the product of the three functions i.e

(x+5)²(x²+5)

This hives the required expression.

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dmitriy555 [2]

Answer:

I think is 18

Step-by-step explanation:

because is the same of the L

7 0
2 years ago
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