Answer:
HCl(aq) + KOH(aq) ===> H2O(l) + KCl(aq)
Note the stoichiometry of the balanced equations shows us that HCl and KOH react in a 1:1 mole ratio. So, let us find moles of HCl and moles of KOH that are present:
moles HCl = 250.0 ml x 1 L/1000 ml x 0.25 mol/L = 0.06250 moles HCl
moles KOH = 200.0 ml x 1 L/1000 ml x 0.40 mol/L = 0.0800 moles KOH
You can see that there are more moles of KOH than there are of HCl, meaning that KOH is in excess and after neutralizing all of the HCl, the solution will be left with excess KOH making the pH > 7 = BASIC
Answer:
d. each of the above (A, B, and C) occurs.
Explanation:
When an ionic species dissolves in water , the ionic compound dissociates into cation and anion , and the cation interacts with the negative end of the water molecules , and the anion interacts with the positive end of the water molecule .
During the process of dissolution , the interaction between , solvent - solute overcome the interaction between solute - solute molecules .
Hence , From the question , all the statement given are correct .
(the heat bomb calorimeter gained)=(the heat material A gave)
r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ
2.741g of material A made 63.16kJ
the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g
