Answer:
Explanation:
HCl is strong acid, hence 0.04M of acid
= 0.057 M of H+
pH = -log [H+]
= -log [0.057]
= 1.244
Let the dissociation of trichloroacetic acid be:
HClO4 --> H^+ + ClO4^-
HA --> H+ + A-
0.072 - x x x
[H+] = 0.057 M
[HA] = 0.072 - 0.057
= 0.015 M
[H+] = [A-] = 0.057
Ka = [H+][A-]/[HA]
= (0.057^2)/(0.015)
= 0.217
= 0.22.
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