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3241004551 [841]
3 years ago
12

What is 31/4 + -11/2 + 21/4

Mathematics
2 answers:
Basile [38]3 years ago
6 0
31/4 + -11/2 + 21/4 = 7 1/2
Hope this helps!
Andrei [34K]3 years ago
6 0
Hope this helped, and GOOD LUCK! :D

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The middle school dance team had 2 separate car washes on Saturday to raise money for new uniforms. The Main Street location rai
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Answer:

$465 at Back Street

$515 at Main Street

Step-by-step explanation:

980 (total) - 50 (the difference between the two) = 930

930/2 = 465 (back street)

465 + 50 (the difference) = 515 ( main street)

CHECK: 465 + 515 = 980

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800 students are going on a school trip by bus.
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The answer is twenty four
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When x is divided by 5 the remainder is 4 and when x is divided by 9 the remainder is 0 what is x?
Marrrta [24]
The number could be any multiple of nine that ends in 4 or 9, like 9, 54, 99, 144, etc.
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3 years ago
Simplify the expression 2 (2 + 4y) + 3x.<br> PLS ANSWER ASAP DUE 9:20
Novay_Z [31]

Answer:

5x+8y

Step-by-step explanation:

We can first open the brackets by using the distrubitive propety.

2(x+4y)+3x

2x+8y+3x

Now we can combine like terms.

5x+8y.

I combined the 3x and the 2x. This works because imagined I have 3 of something then I got 2 more of that something I would now have 5 of that something.

Hoped this helped,

JoeLouis2

7 0
3 years ago
. (0.5 point) We simulate the operations of a call center that opens from 8am to 6pm for 20 days. The daily average call waiting
SashulF [63]

Answer:

The 95% t-confidence interval for the difference in mean is approximately (-2.61, 1.16), therefore, there is not enough statistical evidence to show that there is a change in waiting time, therefore;

The change in the call waiting time is not statistically significant

Step-by-step explanation:

The given call waiting times are;

24.16, 20.17, 14.60, 19.79, 20.02, 14.60, 21.84, 21.45, 16.23, 19.60, 17.64, 16.53, 17.93, 22.81, 18.05, 16.36, 15.16, 19.24, 18.84, 20.77

19.81, 18.39, 24.34, 22.63, 20.20, 23.35, 16.21, 21.73, 17.18, 18.98, 19.35, 18.41, 20.57, 13.00, 17.25, 21.32, 23.29, 22.09, 12.88, 19.27

From the data we have;

The mean waiting time before the downsize, \overline x_1 = 18.7895

The mean waiting time before the downsize, s₁ = 2.705152

The sample size for the before the downsize, n₁ = 20

The mean waiting time after the downsize, \overline x_2 = 19.5125

The mean waiting time after the downsize, s₂ = 3.155945

The sample size for the after the downsize, n₂ = 20

The degrees of freedom, df = n₁ + n₂ - 2 = 20 + 20  - 2 = 38

df = 38

At 95% significance level, using a graphing calculator, we have; t_{\alpha /2} = ±2.026192

The t-confidence interval is given as follows;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

Therefore;

\left (18.7895- 19.5152 \right )\pm 2.026192 \times \sqrt{\dfrac{2.705152^{2}}{20}+\dfrac{3.155945^2}{20}}

(18.7895 - 19.5125) - 2.026192*(2.705152²/20 + 3.155945²/20)^(0.5)

The 95% CI = -2.6063 < μ₂ - μ₁ < 1.16025996668

By approximation, we have;

The 95% CI = -2.61 < μ₂ - μ₁ < 1.16

Given that the 95% confidence interval ranges from a positive to a negative value, we are 95% sure that the confidence interval includes '0', therefore, there is sufficient evidence that there is no difference between the two means, and the change in call waiting time is not statistically significant.

6 0
2 years ago
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