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Oduvanchick [21]
2 years ago
6

Find the area of the shaded region.

Mathematics
2 answers:
kolbaska11 [484]2 years ago
8 0

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

kow [346]2 years ago
7 0

Answer:

<h2>39 in2</h2>

Step-by-step explanation:

<h2>Have a nice day.</h2>

<h2>Thanks. </h2>
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allochka39001 [22]

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3 years ago
An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the
DedPeter [7]

<em><u>The inequality can be used to find the interval of time taken by the object to reach the height  greater than 300 feet above the ground is:</u></em>

d = -16t^2 + 1000

<em><u>Solution:</u></em>

<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the  formula:</u></em>

d = -16t^2 + 1000

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

-16t^2 + 1000 > 300

Solve the inequality

Subtract 1000 from both sides

-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700

16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61

Time cannot be negative

Therefore,

t < 6.61

And the inequality used  is: -16t^2 + 1000>300

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3 years ago
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abruzzese [7]
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2 years ago
A car went 64 miles on 2 gallons of gas in the morning, 16 miles on 1/2 gallon of gas at noon, and 32 miles on 1 gallon of gas a
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Answer:

Yes,

Step-by-step explanation:

You take 64 miles for 2 gallons and divide it by 2. And it leads up to 32 miles and 1 gallon. Now you divide that by 2 again and get 16 miles and 1/2 gallon. So, to check that you can take 16+16 and you get 32 and take 32+32 and you get 64.

7 0
2 years ago
Which piece of additional information can be used to prove that △rst ~ △vut? rt = st 3st = ut ∠r ≅ ∠v ∠v ≅ ∠u
Sunny_sXe [5.5K]

The option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

<h3>What is the similarity law for triangles?</h3>

It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have given two triangles:

Triangle RST and Triangle VUT

AS we can see Line segment RS and UV are parallel.

Which is crossed by a transversal RV.

The angle SRV = Angle RVU

Thus, the option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

Learn more about the similarity of triangles here:

brainly.com/question/8045819

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