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Zolol [24]
2 years ago
10

What is the area of triangle ABC Round to the nearest

Mathematics
2 answers:
scoray [572]2 years ago
6 0

Answer:

A=61.8\ units^2

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of triangle ABC applying the law of sines is equal to

A=\frac{1}{2}(AC)(BC)sin(C)

substitute the given values

A=\frac{1}{2}(10)(13)sin(72^o)

A=61.8\ units^2

Pani-rosa [81]2 years ago
5 0

Answer:

c) 61.8 square units

Step-by-step explanation:

just took the test

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Factor out a negative 1 from each expression. - 4 - (5 + 3)​
ddd [48]

Answer:

-12

Step-by-step explanation:

-4-(5+3)

-4-(8)

-4-8

-12

6 0
3 years ago
State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
A total of 585 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 fewer stu
natulia [17]

Answer:

325

Step-by-step explanation:

Total Tickets = 585

Let the adult tickets be = x

If 65 fewer student tickets were sold than adult tickets then Student tickets = x-65

Student Tickets + Adult Tickets = 585

x + (x-65) = 585

x + x - 65 = 585

2x - 65 = 585

2x = 585 + 65

2x = 650

2x/2 = 650/2

x = 325

Answered by Gauthmath

3 0
2 years ago
!(URGENT)! True or False
sergeinik [125]

its false

im sure

hope it helps!

thanks!

8 0
3 years ago
Read 2 more answers
How do I turn this into a radical?
dimaraw [331]
6sqrt(2) i’m pretty sure
7 0
2 years ago
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