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padilas [110]
4 years ago
10

The length of a rectangular garden is 10 yards and it’s width is 10 feet. What is the perimeter of the garden in feet

Mathematics
1 answer:
ollegr [7]4 years ago
8 0

Answer: 80 feet

Step-by-step explanation:

10 yard= 30 feet

2[l + b]

2{30+10}

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Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.
LenKa [72]

Answer:- B. No, because the corresponding congruent angles listed are not the included angles.


Explanation:-

Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD.

Now, look at the attachment

We can see that ∠X and ∠C are not included angles by the corresponding equal sides.

⇒ We cannot use SAS postulate to show ΔWXY ≅ ΔBCD .

⇒ B is the right option.

SAS postulate tells the if two sides of a triangle and their included angle is equal to the two sides of a triangle and their included angle of another triangle then the two triangles are congruent.

5 0
3 years ago
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babymother [125]

Answer:

16

Step-by-step explanation:

do the parentheses first to get 4

8/2 x 4

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8 0
2 years ago
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3 3/4 -1 3/14 in simpilist form
lakkis [162]

For this case we must simplify the following expression:

3 \frac {3} {4} -1 \frac {3} {14} =

To do this, we convert the mixed numbers to improper fractions:

\frac {4 * 3 + 3} {4} - \frac {14 * 1 + 3} {14} =\\\frac {15} {4} - \frac {17} {14} =\\\frac {14 * 15-4 * 17} {4 * 14} =\\\frac {210-68} {56} =\\\frac {142} {56} =\\\frac {71} {28} =\\2 \frac {15} {28}

Answer:

\frac {71} {28} = 2 \frac {15} {28}

6 0
3 years ago
Consider an urn containing 8 white balls, 7 red balls and 5 black balls.
weqwewe [10]

Answer + Step-by-step explanation:

1) The probability of getting 2 white balls is equal to:

=\frac{8}{20} \times \frac{7}{19}\\\\= 0.147368421053

2) the probability of getting 2 white balls is equal to:

=C^{2}_{5}\times (\frac{8}{20} \times \frac{7}{19}) \times (\frac{12}{18} \times \frac{11}{17} \times \frac{10}{16})\\=0.397316821465

3) The probability of getting at least 72 white balls is:

=C^{72}_{150}\times \left( \frac{8}{20} \right)^{72}  \times \left( \frac{7}{20} \right)^{78}  +C^{73}_{150}\times \left( \frac{8}{20} \right)^{73}  \times \left( \frac{7}{20} \right)^{77}  + \cdots +C^{149}_{150}\times \left( \frac{8}{20} \right)^{149}  \times \left( \frac{7}{20} \right)^{1}  +\left( \frac{8}{20} \right)^{150}

=\sum^{150}_{k=72} [C^{k}_{150}\times  \left( \frac{8}{15} \right)^{k}  \times \left( \frac{7}{15} \right)^{150-k}]

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1 year ago
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7. previously answered in another question, but last choice is correct

8.  yes a diameter is a chord. A chord is any line that connects 2 points on a circle

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