All categories

3 years ago

The length of a rectangular garden is 10 yards and it’s width is 10 feet. What is the perimeter of the garden in feet

Mathematics

1 answer:

ollegr [7]3 years ago

8 0

Answer: 80 feet

Step-by-step explanation:

10 yard= 30 feet

2[l + b]

2{30+10}

You might be interested in

triangle ABC is reflected across the y-axis and then dilated by a factor of 1/2 centered at the origin. which statement correctl

Nadya [2.5K]

Answer:

Step-by-step explanation:

The reflection preserves the side lengths and angles of triangle ABC. The dilation preserves angles but not side lengths.

5 0

2 years ago

A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a sp

Natali [406]

Answer:

Given:

length of the wire = 0.20 meters

magnetic field strength = 0.45 newtons/amperes meter

speed = 10.0 meters per second

emf = B * l * v

B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds

emf = 0.90 volts

The emf produced is 0.90 volts.

Step-by-step explanation:

6 0

3 years ago

Is there some people who dont wear there retainer and still have straight teeth? cause mine still is

RideAnS [48]

Answer:

I Think Yes!

Step-by-step explanation:

Cause I Also Have A Straight Teeth and Also I Don't Wear Retainer!!

5 0

2 years ago

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

3 years ago

What is 15% of 40?<br> A. 2<br> B. 4<br> C. 5<br> D. 6

stealth61 [152]

Answer:

the answer is 6

Step-by-step explanation:

6............................

8 0

3 years ago

Read 2 more answers