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3 years ago

Which statement best compares a line and a point ?

1 answer:

6 0

Hey there!

The answer for your problem is: a line is a set of 2 or more points in a plane

a point is a specific location in a plane

Let me know if you'd like me to explain how I got this answer!

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There are 27 chocolates in a box, all identically shaped. There 4 are filled with nuts, 8 with caramel, and 15 are solid chocola

AlekseyPX

Answer:

Therefore the required probability is $\frac{30}{351}$ .

Step-by-step explanation:

Two events are dependents event if the occurrence of one of them has effect on the probability of the other.

If A and B are dependents,

then,

P(AB)=P(A)P(B).

Given that,

There are 27 chocolates in a box.

Number of nuts chocolates = 4

Number of caramel chocolates = 8

Number of solid chocolates= 15.

The probability of that a solid candy is drawn is

$=\frac{\textrm{Number of solid chocolate}}{\textrm{Total number of chocolate}}$

$=\frac{15}{27}$ .

After selecting a solid chocolate, the number of chocolate is= (27-1)=26.

The probability that a nut candy is drawn is

$=\frac{\textrm{Number of nut chocolate}}{\textrm{Total number of chocolate}}$

$=\frac{4}{26}$

$=\frac{2}{13}$

Therefore the required probability is

$=\frac{15}{27}\times\frac{2}{13}$

$=\frac{30}{351}$

6 0

2 years ago

Can you help me for 10 minutes?

Mariulka [41]

What do you need help with?

7 0

2 years ago

Read 2 more answers

100 Points | Giving Brainliest to correct answer | Reporting false answers |

soldier1979 [14.2K]

Answer:

1.12/30 which is equals to 2/5

2.9 more students

3.171*1.50 =$25.65

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The sugar content of the syrup is canned peaches is normally distributed. Assumethe can is designed to have standard deviation 5

andreyandreev [35.5K]

Answer: 0.50477

Step-by-step explanation:

Given : The sugar content of the syrup is canned peaches is normally distributed.

We assume the can is designed to have standard deviation $\sigma=5$ milligrams.

The sampling distribution of the sample variance is chi-square distribution.

Also,The data yields a sample standard deviation of $s=4.8$ milligrams.

Sample size : n= 10

Test statistic for chi-square : $\chi^2=\dfrac{s^2(n-1)}{\sigma^2}$

i.e. $\chi^2=\dfrac{(4.8)^2(10-1)}{(5)^2}=8.2944$

Now, P-value = $P(\chi^2>8.2944)=0.50477$ [By using the chi-square distribution table for p-values.]

Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.50477

8 0

2 years ago

Look at the image. (calculus)

mash [69]

<h3>Answer: Choice H) 2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is $\sin^2 x + \cos^2x = 1$

If we were to isolate sine, then,

$\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\$

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, $\cos x = \sqrt{1-\sin^2x}\\\\$

Cosine is also positive in this quadrant.

-------------

So,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2$

Therefore,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2$

is an identity as long as 0 < x < pi/2

5 0

1 year ago

Read 2 more answers