Answer:
-9/4
Step-by-step explanation:
putting these to y/x form it is 9/-10 and -9/-6 which has a difference of -9/4 (hopefully this is correct-)
Answer:
<h2>33.2Km</h2>
Step-by-step explanation:
<h3>Time used for journey = </h3>
13 : 24 - 11 : 32 = 1 : 92
1 : 92 = 1 hour 92 minutes
1 hour 92 minutes = 2 hours 32 minutes
<h3>changing 32 minutes to hours</h3>
1 h = 60 min
x = 32 min
x= 32 /60
x= 8/15 hours
<h3>Adding the 2hours to 8/15 hours</h3>
8/15 h + 2 h = 38 / 15
<h3>Using formula for distance</h3>
Distance = Speed × Time
Distance = 85km / h × 38 /15 h
Distance = 33.15 km
To 1DP = 33.2
“a” would equal 7!! hope this helps :)
If their call lasts 11 minutes the cost will be the same
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.