Well simply just state ur learning goals are. In my opinion I would keep it short and simple but give a bit of detail to it. At most like 6 sentences should be ok and should work as an answer
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
12.3 = y
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj/ hyp
cos 35 = y/15
15 cos 35 = y
12.28728066 = y
To the nearest tenth
12.3 = y
<span>In our equations, you can use the generic form of y = mx + b to determine the y-intercept for the function, with b equal to the y-intercept. For g(x), b =2 and for f(x), b=-1. These values are the y-intercepts for the functions. Based on this, the y-intercept of f(x) is 3 units below the y-intercept of g(x). We know this because we can subtract the b value from f(x) from g(x) to get the difference. Difference = 2 - (-1) = 3.</span>
