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larisa [96]
3 years ago
10

5+5+5+5+2454+76492+69238120+65928

Mathematics
2 answers:
Travka [436]3 years ago
3 0

Answer:

5 + 5 + 5 + 5 + 2454 + 76492 + 69238120 + 65928 = 69383014

Step-by-step explanation:

69383014 is the answer, I used a calculator

Please let me know if Im incorrect

aev [14]3 years ago
3 0

Answer:

5+5+5+5+2454+76492+69238120+65928=69383014

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Find the difference (5a^2+4ab-3b^2)-(-5ab+4b^2+3a^2)
Vesna [10]

Answer:

\boxed{\bold{2a^2+9ab-7b^2}}

Step By Step Explanation:

Remove Parenthesis: (a) = a

\bold{5a^2+4ab-3b^2-\left(-5ab+4b^2+3a^2\right)}

Simplify \bold{-\left(-5ab+4b^2+3a^2\right)}

\bold{5ab-4b^2-3a^2}

Rewrite Equation:

\bold{5a^2+4ab-3b^2+5ab-4b^2-3a^2}

Simplify \bold{5a^2+4ab-3b^2+5ab-4b^2-3a^2}

\bold{2a^2+9ab-7b^2}

- Mordancy

8 0
3 years ago
Read 2 more answers
If a puppy gains eight pounds between veterinarian checkups, what has it gained?
Alex_Xolod [135]
The answer should be "The puppy gained weight only."
5 0
3 years ago
Set up the formula to find the balance after 8 years for a total of $12,000 invested at an annual
Natasha2012 [34]

Answer:

A = 12000(1.0002466)²⁹²⁰

Step-by-step explanation:

The formula for the amount after compound interest is: A = P(1 + i)^{n}

"A" is the amount, or balance.

"P" is the principal, or starting amount/investment.

"i" is the interest rate for each compounding period.

"n" is the number of compounding periods.

The interest rate each compounding period, "i", is calculated with i=r/c

"r" is the annual interest rate in decimal form.

"c" is the compounding frequency. (If compounded annually, c=1. If monthly, c=12.)

The number of compounding periods, "n", is calculated with n=tc.

"t" is the time in years.

"c" is the compounding frequency.

In this problem:

t = 8

P = 12,000

r = 9%, or r = 0.09 for decimal form.

c = 365

Calculate "i" and "n".

i = r/c

i = 0.09/365

i = 0.00024657534

i ≈ 0.0002466

n = tc

n = 8(365)

n = 2920

Substitute these back into the formula:

A = P(1 + i)ⁿ

A = 12000(1+0.0002466)²⁹²⁰

A = 12000(1.0002466)²⁹²⁰

7 0
3 years ago
Select all that apply.
Contact [7]

Answer: i'm pretty sure the only answer that applies is the last one.

Good luck!

5 0
4 years ago
Read 2 more answers
A dessert manufacturer wanted to know if adding a preservative to their cupcakes extended their shelf life before going stale. T
aliina [53]

Answer:

The correct option is C) The results were not statistically significant but were practically significant.

Step-by-step explanation:

Consider the provided information.

They found that the difference in these shelf lives had a p-value of 0.24. Assume an α of 0.05.

We reject the null hypothesis if p value is less than α.

We are fail to reject null hypothesis if p value is greater or equal to α.

Here p value is greater than 0.05.

So, we do not reject null hypothesis and conclude that result is not statistically significant. But, there is a practical difference between 3 days and 7 days.

Therefore, the correct option is C) The results were not statistically significant but were practically significant.

8 0
3 years ago
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