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2 years ago

Rafael spins the pointers of the two spinners shown at the right. Find the probability of each possible sum

Mathematics

1 answer:

seraphim [82]2 years ago

6 0

Step-by-step explanation:

P(sum)= 2

On the left: possible outcome has the value of 1 (1) = $\frac{1}{2}$

On the right: 1 possible outcome has the value of 1 (1)= $\frac{1}{3}$

=> the probability of possible P(sum)= 2

= $\frac{1}{2}$ * $\frac{1}{3}$

= $\frac{1}{6}$

P(sum)= 3

On the left: possible outcome has the value of 1 = $\frac{1}{2}$

On the right: 1 possible outcome has the value of 2 = $\frac{1}{3}$

On the left: possible outcome has the value of 2 = $\frac{1}{2}$

On the right: 1 possible outcome has the value of 1 = $\frac{1}{3}$

=> the probability of possible P(sum)= 3

= $\frac{1}{2}$ * $\frac{1}{3}$ + $\frac{1}{2}$ * $\frac{1}{3}$

= $\frac{1}{3}$

P(sum)= 4

On the left: possible outcome has the value of 1 = $\frac{1}{2}$

On the right: 1 possible outcome has the value of 3 = $\frac{1}{3}$

On the left: possible outcome has the value of 2 = $\frac{1}{2}$

On the right: 1 possible outcome has the value of 2= $\frac{1}{3}$

=> the probability of possible P(sum)= 4

= $\frac{1}{2}$ * $\frac{1}{3}$ + $\frac{1}{2}$ * $\frac{1}{3}$

= $\frac{1}{3}$

P(sum)= 5

On the left: possible outcome has the value of 2 = $\frac{1}{2}$

On the right: 1 possible outcome has the value of 3 = $\frac{1}{3}$

=> the probability of possible P(sum)= 5

= $\frac{1}{2}$ * $\frac{1}{3}$

= $\frac{1}{6}$

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Step-by-step explanation:

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