Well first of all, let's define what an integer is...
Integers are numbers such as -2, -1, 0, 1, 2 etc etc.
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If f(5)=12,
f(6)=0.3*f(6-1)
= 0.3*f(5)
= 0.3*12
= 3/10 * 12
= 36/10
= 3.6
We now know that f(6)=3.6
Now:
f(7)=0.3*f(7-1)
= 0.3*f(6)
= 0.3*3.6
= (3/10) * (36/10)
= 108/100
= 1.08
Answer:
f(7)=1.08
Answer:
The solution of the inequation 
is ![\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)](https://tex.z-dn.net/?f=%5Cleft%28-%5Cinfty%2C-%5Cfrac%7B2%7D%7B3%7D%5Cright%5D%5Ccup%5Cleft%5B%5Cfrac%7B5%7D%7B2%7D%2C%2B%5Cinfty%5Cright%29)
.
Step-by-step explanation:
First of all, let simplify and factorize the resulting polynomial:
Roots are found by Quadratic Formula:
![r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}](https://tex.z-dn.net/?f=r_%7B1%2C2%7D%20%3D%20%5Cfrac%7B%5Cleft%5B-%5Cleft%28-%5Cfrac%7B11%7D%7B6%7D%5Cright%29%5Cpm%20%5Csqrt%7B%5Cleft%28-%5Cfrac%7B11%7D%7B6%7D%20%5Cright%29%5E%7B2%7D-4%5Ccdot%20%281%29%5Ccdot%20%5Cleft%28-%5Cfrac%7B10%7D%7B6%7D%20%5Cright%29%7D%20%5Cright%5D%7D%7B2%5Ccdot%20%281%29%7D)
and 
Then, the factorized form of the inequation is:
By Real Algebra, there are two condition that fulfill the inequation:
a) 
b) 
The solution of the inequation is .
Answer:
no
Step-by-step explanation:
<h3>Answer: Net Increase of 26%</h3>
===================================================
Explanation:
If it increases by 5%, then we use the multiplier 1.05
Think of it like saying 100% + 5% = 1 + 0.05 = 1.05
Similarly, an increase of 20% means we involve 1.20
Combine those multipliers to get: 1.05*1.20 = 1.26
This is a net increase of 26%
Interestingly, we get fairly close to 25% which is what many students might go for (since 5 + 20 = 25). This is a beginner's trap.
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An example:
Let's say the temperature is 20 degrees Celsius (68 degrees Fahrenheit)
An increase of 5% means it moves to 1.05*20 = 21 degrees C
A 20% increase means we go to 1.20*21 = 25.2 degrees C
The shortcut would be to do a 26% increase to get 1.26*20 = 25.2 to help confirm we have the correct combined increase.
Answer:
Yes
Step-by-step explanation:
Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.
When both machines work for 20 minutes
Machine A would produce = 
widget and
Machine B would produce = 
widgets
So we can say that Machine A would produce more widgets than Machine N at that time.
Answer is Yes
