Question

The graph below shows the height of a projectile t seconds after it is launched. If acceleration due to gravity is –16 ft/s2, which equation models the height of the projectile correctly?

Answer 1

Answer:

  see attached

Step-by-step explanation:

The x-coordinate of the vertex is given by ...

  x = -b/(2a)

for f(x) = ax^2 +bx +c.

We see that the vertex is at x = 1, and we are given a = -16. Then we can find "b" from ...

  1 = -b/(2(-16))

  32 = b

We know the y-intercept of the equation is 5 (the starting height), so the equation must be ...

  h(t) = -16t^2 +32t +5 . . . . . matches the last choice