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2 years ago

12

Jenny drove her tractor down a row of her cornfield. She drove at constant velocity of 34metersperminute down the row. The row w

as 680meters long. How long did it take for Jenny to drive down one-quarter of the row?

2 answers:

tamaranim1 [39]2 years ago

7 0

Answer:

5 mins

Step-by-step explanation:

680/4

=170 meters (quarter of 680m)

170/34

=5 mins

VikaD [51]2 years ago

3 0

If you move at a constant rate, you obey the law

$d=st$

where d is the distance, s is the speed and t is the time.

You know that your speed is 34 meters per minute, and that your distance is 680. We can solve the equation for the time and plug the values:

$d=st\iff t=\dfrac{d}{s}=\dfrac{680}{34}=20$

So, if you need to travel only one quarter of the distance, it will take 20/4 = 5 minutes

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Step-by-step explanation:

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$P(0) =\frac{1200}{1+11*1}$

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$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

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$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

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The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

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