Jenny drove her tractor down a row of her cornfield. She drove at constant velocity of 34metersperminute down the row. The row w
2 answers:
If you move at a constant rate, you obey the law
where d is the distance, s is the speed and t is the time.
You know that your speed is 34 meters per minute, and that your distance is 680. We can solve the equation for the time and plug the values:
So, if you need to travel only one quarter of the distance, it will take 20/4 = 5 minutes
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Answer:
length and width = 40 and 10 ft.
Step-by-step explanation:
The perimeter of a rectangular toddler play area is 100 feet.
Perimeter = 2(length + width)
Let the width = w
The length is 10 feet more than 3 times the width. Length = 10+(3w)
now put the values
100 = 2(10+3w + w)
100 = 2w + 20 + 6w
100 = (2w + 6w) + 20
100 = 8w + 20
8w = 100 - 20
w =
w = 10 feet.
Now Length = 10+ (3w)
= 10+( 3 × 10)
= 10 + 30
= 40 feet
Therefore, length = 40 feet and width = 10 feet
Answer:
The coordinates of the explosion is (3300, -2750)
Step-by-step explanation:
I have plot the points and attached to thus answer for easy understanding.
Now, from the question, since station A is the first to hear the explosion, we'll make it the foci of the parabola in the graph I attached and it will be horizontal since the distance between station C and A is much more than that between station B and A. Thus, the reason why station C will have to be the other foci with the hyperbola centred at the origin.
Now, sound travels at a speed of 1100 ft/s and station B is located 1100 ft from station A. Thus, the explosion would likely have occurred at a point on the line x = 3300ft . Since station A is 3300ft from centre C = 3300,hence C² = 3300² = 10,890,000. Since it takes 4 seconds longer for the sound to reach station C than A, the sound has traveled 4(1100)= 4400 ft.
Thus, 4400 = d1 = d2 = 2a
So,2a = 4400 and so, a =2200
a² = 2200² = 4,840,000 where d1 is the distance from station C to the explosion and d2 is the distance from station A to the explosion. To find b², let's use the equation ;
c² = a² + b² and so; b² = c² - a² = 10,890,000 - 4,840,000 = 6,050,000
Equation of hyperbola is given as;
(x²/a²) - (y²/b²) = 1
Plugging in the values of a² and b², we obtain ;
(x²/4,840,000) - (y²/6,050,000) = 1
Since we have deduced that the explosion must occur on the line x= 3300, we'll put in 3300 for x to obtain ;
(3300²/4,840,000) - (y²/6,050,000) = 1
2.25 - 1 = (y²/6,050,000)
y² = (1.25 x 6,050,000)
y² = 7562500
y = √7562500
y = ± 2750
Due to the fact that the explosion will occur at a point further from station B than from station A, the explosion will take place in quadrant 4. Thus, we will take the negative value of y which is - 2750.
So explosion will occur at the coordinate (3300, -2750)
