15abc² = 5abc · 3c
25a³bc = 5abc · 5a²
GCF(15abc²; 25a³bc) = 5abc
X-intercepts are found by factoring. Use the quadratic formula on the first since it's in standard form and you find that your x values are in fact -3 and 7. For the second one, use the Zero Product Property that says that x - 3 = 0 or x + 7 = 0. Therefore, x = 3 and -7. Signs are wrong. So not the second one. As for the third one, if you factor out a 3, your polynomial is exactly the same as the first one which did give us the desired x values. So the third one checks out. If you FOIL out the first one and then apply the quadratic formula you do get x = 3 and -7. So the fourth one checks out too. For the last one, putting it into the quadratic formula gives you x values of 3 and -7, so no to that one. Summary: 1st, 3rd, 4th have zeros of -3 and 7; 2nd and 5th do not.
Choice C, it has the same slope as the given equation without being identical to it like choice a.
Step-by-step explanation:
As ANC are collinear,
AB+BC=AC
so,
18+BC = 41
BC = 41-18
BC = 23 is the answer.
Answer:
about 11 years
Step-by-step explanation:
