The equilibrium reaction is
2 NOBr ⇄ 2 NO + Br₂
The initial molarity of NOBr is 0.174 mol/1 L = 0.174 M. Let's apply the ICE approach which stands for Initial-Change-Equilibrium.
2 NOBr ⇄ 2 NO + Br₂
I 0.174 0 0
C -2x +2x +x
----------------------------------------------------
E 0.174-2x 2x x
Since E for Br₂ is 1.79*10⁻² M, then that means x = 1.79*10⁻² M. We can compute E for the other compounds.
E for NOBr = 0.174 - 2(1.79*10⁻²) = 0.1382 M
E for NO = 2(1.79*10⁻²) = 0.0358 M
The expression for Kc according to the reaction is:
Kc = [NO]²[Br₂]/[NOBr]²
Kc = [0.0358]²[1.79*10⁻²]/[0.1382]²
<em>Kc = 1.2×10⁻³</em>
Answer:
C, increases/decreases
Explanation:
As you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus.
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