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Alinara [238K]
3 years ago
6

When the temperature of the water was 10°C the waterweed did not produce bubbles.

Chemistry
2 answers:
Rashid [163]3 years ago
8 0
She might’ve wanted to wait for the water to reach boiling point to count the bubbles
adell [148]3 years ago
4 0

Explanation:

she could waited for the saturated vapour pressure to equal the prevailing atmospheric pressure

ergo boiling to take place seeing as she had gotten the first indication that boiling had started

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What effect does increasing the concentration of a dissolved solute have on each of the colligative properties?
Igoryamba

Answer:

If we increase the concentration of a dissolved solute, the solution would have a vapor pressure so much low, the boiling temperature for the solution will be so high, freezing point for the solution will be so much low and the osmotic pressure will be higher.

Colligative properties always depends on dissolved particles (solute)

Explanation:

These are the colligative properties

- Vapor pressure lowering

ΔP = P° . Xm

Vapor pressure of pure solvent - Vapor pressure of solution.

If we add more solute, it would raise the Xm, so the solution would have a vapor pressure so much low.

Vapor pressure pure solvent - Vapor pressure solution ↑ = P° . Xm ↑

- Boiling point elevation

ΔT = Kb . m

When we add more solute, we are increasing the molality.

↑T° boiling of solution - T° boiling pure solvent = Kf . m ↑

Boiling temperature for the solution will be so high.

- Freezing point depression

When we add more solute, we are increasing the molality.

ΔT = Kf . m

T° fussion of pure solvent - ↓T° fussion of solution = Kf . m↑

Freezing point for the solution will be so much low.

- Osmotic pressure

π = M . R . T

When we add solute, molarity is increasing. Therefore the osmotic pressure will be higher.

π↑ = M↑ . R . T

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because iron is magnetic and sand is not

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