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Alinara [238K]
2 years ago
6

When the temperature of the water was 10°C the waterweed did not produce bubbles.

Chemistry
2 answers:
Rashid [163]2 years ago
8 0
She might’ve wanted to wait for the water to reach boiling point to count the bubbles
adell [148]2 years ago
4 0

Explanation:

she could waited for the saturated vapour pressure to equal the prevailing atmospheric pressure

ergo boiling to take place seeing as she had gotten the first indication that boiling had started

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What is the mass of 2.071x10^14 molecules of SF2
kolezko [41]

Answer:

Name of molecule Sulfur Difluoride ( SF2)

No of Valence Electrons in the molecule 20

Hybridization of SF2 sp3 hybridization

Bond Angles 98 degrees

Molecular Geometry of SF2 Bent

Explanation:

Sulfur Difluoride is an inorganic molecule made up of one Sulphur atom and two Fluorine atoms. It has a chemical formula of SF2 and can be generated by the reaction of Sulphur Dioxide and Potassium Fluoride or Mercury Fluoride. In this blog post, we will look at the Lewis dot structure of SF2, its molecular geometry and shape.

7 0
3 years ago
A intramuscular medication is given at 5.00mg/kg of body weight. What is the dose in grams for a 180-lb patient?
Alex17521 [72]
0.408 gram for 180-lb patient
7 0
3 years ago
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A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10
lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0
3 years ago
What is 0.000980 in scientific notation
JulijaS [17]

Answer:

9.80x10^-4

Explanation:

5 0
3 years ago
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How many atoms of Hydrogen are in 67.2 L of H2 at STP?​
nekit [7.7K]

Answer:

this answer is hard cant answer

5 0
3 years ago
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