Answer:
The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>
Explanation:
Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M
Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M
<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)
The equilibrium constant () for the given chemical reaction, is given by the equation:
<u><em>At the original equilibrium state:</em></u>
<u><em>Therefore, at the new equilibrium state:</em></u>
<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>
Because of different chemical reactions between the elements<span />
<span>Ionic compounds form crystal lattices, not molecules. The term formula unit is used to indicate the simplest whole-number ratio of ions in the compound.</span>