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QveST [7]
3 years ago
10

For the reaction shown, calculate how many grams of each product form when the following amounts of reactant completely react to

form products. Assume that there is more than enough of the other reactant.
2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(l)

4.3 gAl
Chemistry
1 answer:
stira [4]3 years ago
7 0
This may help you
<span>You need to use some stoichiometry here. The only way to do that is if you're working in moles. Since you're given grams of Al, you can convert that moles by dividing by the molar mass. Then from looking at the coefficients in your equation, you can see that for however many moles of Al react, the same numbers of moles of Fe will be produced, but only half as many moles of Al2O3 will be produced. To go back to grams, multiply the moles of each product that you get by their molar masses!</span>
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A certain half-reaction has a standard reduction potential +0.80 V . An engineer proposes using this half-reaction at the anode
Strike441 [17]

Answer:

a. Minimum 1.70 V

b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

ε⁰ cell = ε⁰ reduction -  ε⁰  oxidation

Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the  oxidized species  0.80 V, thus

ε⁰ reduction -  ε⁰  oxidation ≥  ε⁰ cell

Since ε⁰  oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V )  ≥  0.90 V

⇒ ε⁰ reduction  ≥ 1.70 V

Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

8 0
3 years ago
8. Write a balanced chemical equation showing how you could prepare each of the following salts from an
polet [3.4K]

Answer:

according to my reading

use own words

Explanation:

Salts are combinations of acids and bases. The cation comes from a base and the anion from an acid. Therefore, to make KNO3 we react KOH and HNO3. See how that is done? We write K and add OH to make KOH. We take NO3 and add H to make HNO3.

6 0
3 years ago
Calculate the solubility of carbon dioxide at 400 kPa.
BaLLatris [955]

The solubility of carbon dioxide at 400 kPa  at room temperature is ;

( B ) 0.61 CO2/L

<u>Given data </u>

pressure of CO₂ = 400 Kpa = 3.95 atm

Kh of CO₂ = 3.3 * 10⁻² mol/L.atm

<h3>Calculate the solubility of carbon dioxide </h3>

Solubility = pressure * Kh value of CO₂

                = 3.95 atm * 3.3 * 10⁻² mol / L.atm

                = 0.13 mol/l  CO₂

                = 0.61 CO₂ / L

Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l  CO₂.

Learn more about solubility : brainly.com/question/23946616

From the options the closest answer is ( B ) 0.61 CO₂ / L

7 0
2 years ago
HELP ASAP I WILL GIVE BRAINLIEST
alina1380 [7]

Answer:

it can last for 30 minutes

Explanation:

because it is very good at giving off heat, extothermal heat can last for quite a while.

3 0
2 years ago
How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??
GarryVolchara [31]
The atoms  of  hydrogen  that are  present  in  7.63 g  of ammonia(NH3)

find  the  moles  of NH3 =mass/molar mass
 7.63 g/ 17 g/mol = 0.449  moles

since there  is  3 atoms of H  in NH3 the  moles of  H = 0.449 x 3 = 1.347 moles

by  use  of  1 mole = 6.02 x10^23  atoms
what  about  1.347  moles

= 1.347  moles/1   moles  x 6.02 x10^23 atoms = 8.11 x10^23  atoms of Hydrogen
3 0
3 years ago
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