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AysviL [449]
3 years ago
9

Professor Whitney has a sample of lead and a sample of iron. The samples have equal mass. When Whitney heats the samples, the le

ad reaches a higher temperature than the iron, even though both samples absorbed the same amount of thermal energy. What can Whitney conclude from this experiment?
Chemistry
1 answer:
Juliette [100K]3 years ago
3 0
Iron radiates energy faster than lead. Iron has higher heat conductivity than lead.





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Answer: True

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Which of the following would be a good use for a nonmetal? handle of frying pan electrical wires structural components in buildi
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Handle of frying pan would be a good use for a nonmetal. A nonmetal is neither a good thermal insulator nor a good electrical conductor. Because it is neither, it can be use as a semiconductor. It does not absorb heat that much that is why it is best in insulating.

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What is the final concentration of cl- ion when 250 ml of 0.20 m cacl2 solution is mixed with 250 ml of 0.40 m kcl solution? (as
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CaCl2 and KCl are both salts which dissociate in water when dissolved. Assuming that the dissolution of the two salts are 100 percent, the half reactions are:

<span>CaCl2 ---> Ca2+  +  2 Cl-</span>

KCl ---> K+ + Cl-

Therefore the total Cl- ion concentration would be coming from both salts. First, we calculate the Cl- from each salt by using stoichiometric ratio:

Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles Cl / 1 mole CaCl2)

Cl- from CaCl2 = 0.1 moles

 

Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1 mole KCl)

Cl- from KCl = 0.1 moles

 

Therefore the final concentration of Cl- in the solution mixture is:

Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)

Cl- = 0.2 moles / 0.5 moles

<span>Cl- = 0.4 moles             (ANSWER)</span>

6 0
3 years ago
What is a change in a substance that does not involve the identity of the substance
GenaCL600 [577]

The answer to this would be a physical change. Physical changes are changes that affect the form of a chemical substance, but not the chemical composition itself. Hope this helped!


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3 years ago
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In a 0.01 M solution of 1,4-butanedicarboxylic acid, HOOCCH2CH2COOH (Ka1 = 2.9 x 10-5,
azamat

Answer:

The correct answer is B) HOOCCH2CH2COOH(aq)

Explanation:

Both Ka1 and Ka2 are low, so the acid will dissociate only slightly into HOOCCH2CH2COO- ions and even more slightly into -OOCCH2CH2COO- ions. The concentration of hydronium ions (H₃O⁺) will be consequently low. The species that will be in the highest concentration will be HOOCCH2CH2COOH (the weak acid not dissociated).

8 0
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