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Marrrta [24]
3 years ago
7

How many moles of sodium ions are present in 0.25 kg of a 2.0 m solution of sodium chloride in water

Chemistry
1 answer:
LenKa [72]3 years ago
8 0

0.50 is the answer on edge

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A common function of proteins and carbohydrates in the plasma membrane is...
Vika [28.1K]
I believe your answer is B.
8 0
3 years ago
If an individual is eating a diet in which 25% of their ATP production is a result of utilizing carbohydrates, 50% of their ATP
NISA [10]

Answer:

Oxidative phosphorylation proceeds with the formation of energy laden molecules i.e; carbondioxide and water.

Therefore, Total CO₂ production is directly related to VCO₂ = R x VO₂

where, R is the respiratory quotient varing among 0.7 to 1.0 according to the energy intake (ATP) ie 0.25 of the total diet consumed .

VO₂ is, as mentioned above arterial venous oxygen difference = 6.2ml/dl

therefore, VCO₂ = 0.25 x 6.2

= 1.55 ml/dl

ie; VO₂ : VCO₂ = 6.2 : 1.55.

Explanation:

5 0
2 years ago
Calculate no. Of moles in 329g of H2so4
Anestetic [448]
Mol= mass (grams) /Mr
Mr of Sulfuric Acid (H2SO4): 98
mol= 329/98
=3.36 moles
8 0
2 years ago
How many moles of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)
yuradex [85]

Answer:

0.20 mol

Explanation:

Let's consider the reduction of iron from an aqueous solution of iron (II).

Fe²⁺ + 2 e⁻ ⇒ Fe

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

5.6 g × 1 mol/55.85 g = 0.10 mol

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are

0.10 mol Fe × 2 mol e⁻/1 mol Fe = 0.20 mol e⁻

7 0
3 years ago
The chemical formula for ferric sulfate is Fe(SO4)3. Determine the following:
Lyrx [107]

Answer :

(a) The number of sulfur atoms are, 31.61\times 10^{23}.

(b) The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(c) The number of moles of Fe_2(SO_4)_3 is, 8.63\times 10^{-3}mole

(d) The mass of the mass of Fe_2(SO_4)_3 is, 19.95\times 10^{-22}g

Explanation :

(a) As we are given the number of moles of Fe_2(SO_4)_3 is, 1.75 mole. Now we have to calculate the number of sulfur atoms.

In the Fe_2(SO_4)_3, there are 2 iron atoms, 3 sulfur atoms, 12 oxygen atoms.

As, 1 mole of Fe_2(SO_4)_3 contains 3\times 6.022\times 10^{23} number of sulfur atoms.

So, 1.75 mole of Fe_2(SO_4)_3 contains 1.75\times 3\times 6.022\times 10^{23}=31.61\times 10^{23} number of sulfur atoms.

The number of sulfur atoms are, 31.61\times 10^{23}

(b) As we are given the number of moles of Fe_2(SO_4)_3 is, 2.65 mole. Now we have to calculate the mass of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

\text{Mass of }Fe_2(SO_4)_3=2.65mole\times 399.88g/mole=1059.682g

The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(c) As we are given the mass of Fe_2(SO_4)_3 is, 3.45 grams. Now we have to calculate the moles of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

3.45g=\text{Moles of }Fe_2(SO_4)_3\times 399.88g/mole

\text{Moles of }Fe_2(SO_4)_3=8.63\times 10^{-3}mole

The number of moles of Fe_2(SO_4)_3 is, 8.63\times 10^{-3}mole

(d) As we are given the formula unit of Fe_2(SO_4)_3 is, 3. Now we have to calculate the mass of Fe_2(SO_4)_3.

As we know that 1 mole of Fe_2(SO_4)_3 contains 6.022\times 10^{23} formula unit.

Formula used :

\text{Formula unit of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}

3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}

\text{Moles of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole

Now we have to calculate the mass of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

\text{Mass of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole\times 399.88g/mole=19.95\times 10^{-22}g

The mass of the mass of Fe_2(SO_4)_3 is, 19.95\times 10^{-22}g

6 0
3 years ago
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