Pip 4 Tweaking the data

PLEASE HELP I WILL GIVE BRAINLEST

Korvikt [17]

Answer:

Angle WZY=31degrees

Step-by-step explanation:

5x+11=8x-1

11+1=8x-5x

12=3x

X=12/3

X=4

Substitute x=4 in 5x+11

5(4)+11=31

6 0

3 years ago

How do you evaluate sin(13π/12)?

Alekssandra [29.7K]

13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0

Recall the double angle identity,

sin^2(x) = (1 - cos(2x))/2

If we let x = 13pi/12, then

sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]

where we took the negative square root because we expect a negative value.

Now, because cosine has a period of 2pi, we have

cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2

Then

sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]

sin(13pi/12) = - sqrt[2 - sqrt[3]]/2

7 0

3 years ago

Describe or show two ways to find the following product: 1/4 x 2/3.

Anon25 [30]

1/4 = 0.25
2/3 = 0.666666667
0.25(0.666666667) = 0.166666667 = $\frac{1}{6}$
______________________________

$\frac{1}{4} ( \frac{2}{3}) = \frac{2}{12} = \frac{1}{6} = 0.166666667$

7 0

3 years ago

What is an equation for the linear function whose graph contains the points (-1,-2) and (3,10) enter your answers in the boxes

mr Goodwill [35]

The equation for the linear function whose graph contains the points (-1, -2) and (3, 10) is y = 3x + 1

<h3>Solution:</h3>

Given that linear function whose graph contains the points (-1, -2) and (3, 10)

We have to find the equation of line

Any function of the form f (x) = m x + b, where m is not equal to 0 is called a linear function

So let us use the slope intercept form

The slope intercept form is given as:

y = mx + c

Where "m" is the slope of line and "c" is the y - intercept

Let us first find slope of line containing points (-1, -2) and (3, 10)

The slope of line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text {Here } x_{1}=-1 \text { and } y_{1}=-2 \text { and } x_{2}=3 \text { and } y_{2}=10$

$m=\frac{10-(-2)}{3-(-1)}=\frac{12}{4}=3$

Thus the slope of line is "m" = 3

Substitute m = 3 and (x, y) = (-1, -2) in y = mx + c

-2 = 3(-1) + c

-2 = -3 + c

c = -2 + 3 = 1

Now substitute c = 1 and m = 3 in slope intercept form to get equation of line

y = 3x + 1

Thus the equation for the linear function is found out

6 0

4 years ago

Write the equation of the line that passes through the points (2 , -1) and has a slope of - 3

svetlana [45]

Answer:

y=-3x+5

Step-by-step explanation:

y=mx+b

m=slope or gradient (=-3)

y=-3x+b

Add your points

(2, -1)

-1=(-3 x 2)+b

-1= -6+b

-1+6=b

b=5

y=-3x+5

5 0

3 years ago

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