Given:
M=(x1, y1)=(-2,-1),
N=(x2, y2)=(3,1),
M'=(x3, y3)= (0,2),
N'=(x4, y4)=(5, 4).
We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.
For a parallelogram, opposite sides are equal
If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.
To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,
Slope of MN= Slope of M'N'.
Slope of MM'=NN'.

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.
Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.
Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.
Answer:
40:16, 16:40, 40/16, 16/40
Answer: A and B
Step-by-step explanation:
The shape is moving from right to left and down
Answer:
13R - (-14)
Step-by-step explanation:
I believe this is the right answer i really hope it is im sorry if its wrong
Have a good day!
Answer:
The answer is "
"
Step-by-step explanation:
Please find the graph file.
![h= y=2x-x^2\\\\r= x\\\\Area=2\pi\times r\times h\\\\= 2 \pi \times x \times (2x-x^2)\\\\= 2 \pi \times 2x^2-x^3\\\\volume \ V(x)=\int \ A(x)\ dx\\\\= \int^{x=1}_{x=0} 2\pi (2x^2-x^3)\ dx\\\\= 2\pi [(\frac{2x^3}{3}-\frac{x^4}{4})]^{1}_{0} \\\\= 2\pi [(\frac{2}{3}-\frac{1}{4})-(0-0)] \\\\= 2\pi \times \frac{5}{12}\\\\=\frac{5\pi}{6}\\\\](https://tex.z-dn.net/?f=h%3D%20y%3D2x-x%5E2%5C%5C%5C%5Cr%3D%20x%5C%5C%5C%5CArea%3D2%5Cpi%5Ctimes%20r%5Ctimes%20h%5C%5C%5C%5C%3D%202%20%5Cpi%20%5Ctimes%20x%20%5Ctimes%20%282x-x%5E2%29%5C%5C%5C%5C%3D%202%20%5Cpi%20%5Ctimes%202x%5E2-x%5E3%5C%5C%5C%5Cvolume%20%5C%20V%28x%29%3D%5Cint%20%5C%20A%28x%29%5C%20dx%5C%5C%5C%5C%3D%20%5Cint%5E%7Bx%3D1%7D_%7Bx%3D0%7D%202%5Cpi%20%282x%5E2-x%5E3%29%5C%20dx%5C%5C%5C%5C%3D%202%5Cpi%20%5B%28%5Cfrac%7B2x%5E3%7D%7B3%7D-%5Cfrac%7Bx%5E4%7D%7B4%7D%29%5D%5E%7B1%7D_%7B0%7D%20%5C%5C%5C%5C%3D%202%5Cpi%20%5B%28%5Cfrac%7B2%7D%7B3%7D-%5Cfrac%7B1%7D%7B4%7D%29-%280-0%29%5D%20%5C%5C%5C%5C%3D%202%5Cpi%20%5Ctimes%20%5Cfrac%7B5%7D%7B12%7D%5C%5C%5C%5C%3D%5Cfrac%7B5%5Cpi%7D%7B6%7D%5C%5C%5C%5C)