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gavmur [86]
3 years ago
15

Which statement is true?

Chemistry
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

A

Explanation:

The entropy of a system has to deal with how energy is stored in a system. It tends to looks at the degree of disorderliness in the system.

The spontaneity of a reaction deals with the possibilities of the reactions occurring, while an exothermic reaction is one in which energy is released to the surroundings, the change in enthalpy here is negative.

The change in entropy or the change in enthalpy cannot dictate if a reaction is feasible I.e spontaneous or not. What determines the spontaneity of a chemical reaction is the change in free energy. For a reaction to be spontaneous, this value must be negative.

The change in free energy, the enthalpy and entropy are connected by the equation below:

ΔG = ΔH - TΔS

Now back to the question, for the first option, we were told that entropy increased and system is exothermic meaning negative enthalpy and positive entropy. In this case , change in free energy will be negative over all temperatures and hence, the reaction is spontaneous.

To the second option, we have negative entropy and negative enthalpy. Here change in free energy will only be negative at low temperature, which of course is not the best answer here

To the third option, we have negative entropy and positive enthalpy. This means change in free energy is only negative at high temperatures which of course is not the best answer.

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  The empirical   formula  of hydrocarbon is C₃H₈

The  molecular formula of hydrocarbon   is C₆H₁₆


<u><em> Empirical  formula  calculation</em></u>

Hydrocarbon  contain  carbon and hydrogen

  Step 1:  find the  mass  carbon (C) in carbon dioxide (CO₂)  and hydrogen (H )  in water

mass of  of element = molar mass  of element/ molar mass molecule x total mass of    molecule

From periodic table the molar mass  of C =12,    for CO₂ = 12+( 16 x2) =44 g/mol,     for H = 1.00 g/mol,    for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom  of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H  is therefore =  2/18 x 1.442 =0.1602 g


Step 2:  find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060  moles

moles of H  =  0.1602÷ 1 g/mol = 0.1602 moles


Step 3: find the mole ratio  of C and H by dividing  each  mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

  For H = 0.1602/0.06 =2.67

multiply   by 3  to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈


<u><em>The molecular formula calculation</em></u>

[C₃H₈]n  = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂   = C₆H₁₆



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