Explanation:
To get a better understanding of the answer,let's take use of Fajan's rule which says that no bond is neither purely covalent or purely ionic.
For ionic compounds MP and BP are higher than covalent compounds. So in order to find the one with higher MP,it's enough to find the most ionic compound among the given options.
In LiF,LiCl,LiBr and LiI,The cation is same and anion only differs.According to Fajans rule Smaller anion and larger cation favours ionic bonding and vice versa. Since Fluoride is the smallest anion,LiF is the most ionic compound and hence it is the one with highest MP from the options.Hope it helps
Answer:
7.26 moles of NH₃ are formed in this reaction
Explanation:
This is about the reaction for the production of ammonia
1 mol of nitrogen gas reacts to 3 moles of hydrogen in order to produce 2 moles of ammonia.
The equation is: N₂ + 3H₂ → 2NH₃
In the question, we were informed that the excess is the H₂ so the N₂ is limiting reagent. We determine the moles, that has reacted:
101.7 g / 28 g/mol = 3.63 moles
So, If 1 mol of nitrogen gas can produce 2 moles of ammonia
3.63 moles of N₂ must produce ( 2 . 3.63) / 1 = 7.26 moles of NH₃
18 valance electrons, Hope this helps!
