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4 years ago

How much does 8.20 X 10-3dm3 (1dm3 = 1L) sample of aluminum weigh in grams? centimeters?

Mathematics

1 answer:

m_a_m_a [10]4 years ago

7 0

Answer:

8.20 grams ; 8.20 cm³

Step-by-step explanation:

At first convert it to m³ from dm³

we know,

1 dm³ =10⁻³ m³

∴ 8.20 X 10⁻³dm3 = 8.20 X 10⁻³ x 10⁻³ m³

=8.20 X 10⁻⁶ m³

m³ to gram :

1 m³ = 10⁶ grams

∴ 8.20 X 10⁻⁶ m³ = (8.20 X 10⁻⁶x10⁶) grams

= 8.20 grams

m³ to cm³ :

1m³ = 10⁶ cm³

∴8.20 X 10⁻⁶ m³ = (8.20 X 10⁻⁶ x 10⁶) cm³

=8.20 cm³

Note:

1 cm³ = 1 gram

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Write the ratio as a fraction in lowest terms. Compare in inches, 2 feet to 45 inches

ololo11 [35]

Answer:

8 to 15

Step-by-step explanation:

2 feet times 12 inches is 24 and it is to 45 inches. You then need to simplify 24 and 45 by 3 to get 8 and 15 and to get the ratio 8 to 15.

Hope this helps!

6 0

3 years ago

Imagine these are your students' test scores (out of 100): 63, 66, 70, 81, 81, 92, 92, 93, 94, 94, 95, 95, 95, 96, 97, 98, 98, 9

lions [1.4K]

Answer:

The mean ≈ 90

The median = 95

The mode = 95 & 100

The range = 37

Step-by-step explanation:

We will base out conclusion by calculating the measures of central tendency of the distribution i.e the mean, median, mode and range.

– Mean is the average of the numbers. It is the total sum of the numbers divided by the total number of students.

xbar = Sum Xi/N

Xi is the individual student score

SumXi = 63+66+70+81+81+92+92+93+94+94+95+95+95+96+97+98+98+99+100+100+100

SumXi = 1899

N = 21

xbar = 1899/21

xbar = 90.4

xbar ≈ 90

Hence the mean of the distribution is approximately equal to 90.

– Median is number at the middle of the dataset after rearrangement.

We need to locate the (N+1/2)the value of the dataset.

Given N =21

Median = (21+1)/2

Median = 22/2

Median = 11th

Thus means that the median value falls on the 11th number in the dataset.

Median value = 95.

Note that the data set has already been arranged in ascending order so no need of further rearrangement.

– Mode of the data is the value occurring the most in the data. The value with the highest frequency.

According to the data, it can be seen that the value that occur the most are 95 and 100 (They both occur 3times). Hence the modal value of the dataset are 95 and 100

– Range of the dataset will be the difference between the highest value and the lowest value in the dataset.

Highest score = 100

Lowest score = 63

Range = 100-63

Range = 37

8 0

3 years ago

Write an equivalent exponential equation for: <img src="https://tex.z-dn.net/?f=log_%7B2%7D%20%28%5Cfrac%7B1%7D%7B4%7D%20%29

Kisachek [45]

Answer: $\frac{1}{4}=2^{(-2)}$

Step-by-step explanation:

You know that an expression written is logarithmic form is:

$x=log_b(y)$

And an expression equivalent to the expression above that is written in exponential form is:

$y=b^x$

Therefore, keeping the information above on mind, you have that an equivalent exponential equation for $log_{2}(\frac{1}{4}) =-2$ , is the shown below:

$\frac{1}{4}=2^{(-2)}$

5 0

3 years ago

Read 2 more answers

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Eva8 [605]

The answer is p - 4 since he did 4 more problems then him and we don’t know how many p is it’d have to be p-4

7 0

3 years ago

An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating. An independent testing firm has been contra

d1i1m1o1n [39]

Answer:

The calculated value z = 1.3145 < 2.326 at 0.02 level of significance

The null hypothesis is accepted

Hence An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating.

Step-by-step explanation:

Step(i):-

An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating.

The mean of the Population 'μ' = 28.0miles/gallon

Given data after testing 270 cars, they found a mean MPG of 27.8. Assume the variance is known to be 6.25.

The sample size 'n' = 270

Mean of the sample 'x⁻' = 27.8

Given Population variance 'σ² = 6.25

The standard deviation of Population 'σ' = √6.25 = 2.5

Step(ii):-

Null hypothesis :H₀: 'μ' = 28.

Alternative hypothesis :H₁: 'μ' ≠28.

The test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{27.8-28 }{\frac{2.5}{\sqrt{270} } } = \frac{-0.2}{0.15214}$

Z = -1.3145

|Z| = |-1.3145|= 1.3145

Step(iii):-

The tabulated value of z-score at 0.02 level of significance = 2.326

The calculated value z = 1.3145 < 2.326 at a t 0.02 level of significance

The null hypothesis is accepted

Hence An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating.

8 0

4 years ago