Answer:
Option C
Step-by-step explanation:
You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.
The total cost has to be in units of $.
There are two types of costs in the problem:
Those that depend on the number of days ($/day
)
Those that depend on the number of students and the number of days ($/(student * day))
If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'
So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:
3 days (Cost of training + Cost of food Miscellaneous expenses :).
Therefore the correct answer is option C:
C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.
The expression that represents the total expense should have a formula similar to this:
y = 3 ($ 100b + $ 200) + $ 1050
Answer:
x = 16.6
Step-by-step explanation:
Since we know the measure of an acute angle (31 degrees) of a right angle triangle, and of the side opposite to the angle (10), and we need to find the measure of the adjacent side "x", we use the tangent function:
which rounded to one decimal is
x = 16.6
I don’t see a diagram, but I assume that you must use these things.
Opposite interior angles. (Which are equal)
Same side interior angles (which are supplementary or they add up to 180)
Corresponding angles (which are equal)
Vertical angles (which are equal)
86% if im correct, i got this answer because of the standard deviation, even though, im not 100% sure im correct, do some researching for this answer on top of mine!
According to given conditions, m+n is equal to 409.
Consider the diagram below.
In the hexagon ABCDEF, let
AB = BC = CD = 3;
DE = EF = FA = 5;
Arc BAF is equal to one-third of the circle's circumference.
Hence, ∠BCF = ∠BEF = 60°;
Similarly, ∠CBE = ∠CFE = 60°;
Let the point of intersection of BE and CF be P, BE and AD be Q and CF and AD be R.
∴ Δ EFP and Δ BCP are equilateral, and so Δ PQR is also equilateral.
Also, ∠ BAD and ∠ BED subtend the same arc and so do ∠ ABE and ∠ ADE.
∴ Δ ABQ is similar to Δ EDQ
Also,
and
On solving these simultaneous equations, we get AD = 360/49
∴ m + n = 409.
To learn more about similarity of triangles, refer to this link:
brainly.com/question/25882965
#SPJ4