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3 years ago

A circle's circumference is approximately 44 cm.

Mathematics

1 answer:

Sav [38]3 years ago

7 0

<h3>Answers</h3><h3>diameter = 14</h3><h3>radius = 7</h3><h3>area = 154</h3>

these are all approximate

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Explanation:

C = pi*d is the formula for the circumference. We know that C = 44 approximately, so,

C = pi*d

d = C/pi

d = 44/3.14

d = 14.01 approximately

d = 14 also approximate

take half of this to get the radius

r = d/2 = 14/2 = 7

Then use this radius to find the circle's area

A = pi*r^2

A = 3.14*7^2

A = 153.86

A = 154 rounding to the nearest whole number

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The equations which are sums of perfect cubes are as follows;

$\rm 8x^6+27x^9+1$

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<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is $\rm 8x^6+27x^9+1$ .

The equation can be written as;

$\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3$

All the terms in the expression are can be represented as perfect cubes.

2. The given equation is $\rm 81x^3+16x^6$ .

The equation can be written as;

$\rm 81x^3+16x^6\\\\9^2x^3+4^2(x^2)3$

In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is $\rm x^6+x^3$ .

The equation can be written as;

$\rm x^6+x^3\\\\(x^2)^3+x^3$

All the terms in the expression are perfect cubes.

4. The given equation is $\rm 27x^9+x^{12}$ .

The equation can be written as;

$\rm 27x^9+x^{12}\\\\3^3(x^3)^3+(x^4)^3$

All the terms in the expression are perfect cubes.

5. The given equation is $\rm 9x^3+27x^9$ .

The equation can be written as;

$\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3$

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

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Read 2 more answers

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Pie

C is the correct answer

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3 years ago