Volume = (1/3) * π * r² * h.
= (1/3) * π * 3² * 4.5.
= (1/3) * 127.23450247
= 42.41115 cm^3
This is a problem of maxima and minima using derivative.
In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:
V = length x width x height
That is:

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:
Surface area of the square base =

Surface area of the rectangular sides =

Therefore, the total area of the cube is:

Isolating the variable y in terms of x:

Substituting this value in V:

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

Solving for x:

Solving for y:

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ftWidth = 4 ftHeight = 2 ftAnd its volume is:
There are 104 cars in the parking lot.
According to statement there are between 90 and 115 cars on the lot.
So, {X| 90 < x < 115} (This renders an infinite solution set finite)
AND exactly one eight of them have a sticker on the back, so the total number of cars must be evenly divisible by eight.
X ∈ {96, 104, 112,}
AND exactly one fourth of the cars are green, so the number of cars must be evenly divisible by 4. Here all above written numbers are divisible by 4. So, find the mean to calculate the number of cars in the parking lot.
x = (96+104+112)/3
x = 104
There are 104 cars in the parking lot.
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The correct answer is 110 degrees
The value of X is 115
If we substitute X, then the “equation” would be (115)-5=110 degrees :))))
Answer:
30.31%
Step-by-step explanation:
Mark up on selling price is given by markup*100%/selling price
In this case, markup is given as $870 while the selling price is $2870 hence the percentage of narkup to selling price will be given by 
Therefore, the percentage of markup to selling price is approximately 30.31%