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anzhelika [568]

2 years ago

15

(no links pls) find the value of m

1 answer:

Nina [5.8K]2 years ago

6 0

Answer:

D.

<P= 5

I hope this helps:)

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The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

How can I find c in a=3 b=4

Dahasolnce [82]

A^2+b^2= c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
5=c

8 0

3 years ago

NEED HELP NOW...NEED CORRECT ANSWER...WILL MARK BRAINLIEST...

alexira [117]

C. First person -hellobrains

7 0

2 years ago

2. help me i will give u brainliest

Likurg_2 [28]

Answer:

the 1st one

Step-by-step explanation:

I passes it in the quiz

3 0

2 years ago

PLEASE HELP!!!!!

Ne4ueva [31]

Answer:

Equation: $30=2(x-2)+2(2x+3)$

$x:\frac{14}{3}$

Step-by-step explanation:

By definition, the perimeter of a figure can be calculated by adding the lenghts of its sides.

Knowing this, you can write the following equation:

$P=2(x-2)+2(2x+3)$ <em> [Equation 1]</em>

According to the data given in the exercise, the perimeter in feet of the fighter is:

$P=30$

Therefore, you can substitute this values into<em> [Equation 1]:</em>

$30=2(x-2)+2(2x+3)$

Finally, you must solve for "x" in order to find its value. This is:

$30=6x+2\\\\30-2=6x\\\\\frac{28}{6}=x\\\\x=\frac{14}{3}$

3 0

2 years ago