In the era just prior to the Reformation, which of the following is true about the Catholic Church?
2 answers:
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The vertex form of the equation of a parabola is given by
where (h, k) is the vertex of the parabola.
Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by
For a = 1,
<span>The parabola whose minimum is at (−12,−2) is given by the equation
, where a = 24 and b = 112.</span>
where (h, k) is the vertex of the parabola.
Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by
For a = 1,
<span>The parabola whose minimum is at (−12,−2) is given by the equation
Answer:
a= 5 and b=1
Step-by-step explanation:
To solve, we will follow the steps below:
2x + 3y = 7
(a-b)x + (a+b)y = 3a + b - 2
We should note that since it has infinitely many solutions then,
Hence
2/a-b = 3/a+b = 7/3a +b-2
2/a-b = 3/a+b
cross-multiply
3(a-b) = 2( a+b)
open the bracket
3a - 3b = 2a + 2b
collect like term
3a - 2a = 2b + 3b
a = 5b -------------------------------------------(1)
Similarly
3/a+b = 7/3a +b-2
cross-multiply
7(a+b) = 3(3a+b -2)
7a + 7b = 9a + 3b -6
take all the variables to the left-hand side of the equation
7a - 9a+ 7b-3b = -6
-2a + 4b = -6 ---------------------------------(2)
but a = 5b
substitute a= 5b in equation (2) and solve for b
-2(5) + 4b = -6
-10 + 4b = -6
add 10 to both-side of the equation
-10 + 10+ 4b = -6+10
4b = 4
divide both-side of the equation by 4
b = 1
substitute b= 1 in equation (1)
a = 5b
a =5(1)
a=5
Therefore, a= 5 and b=1