Answer:
f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
(f – g)(x) = f (x) – g(x)
= [3x + 2] – [4 – 5x]
= 3x + 2 – 4 + 5x
= 3x + 5x + 2 – 4
= 8x – 2
(f × g)(x) = [f (x)][g(x)]
= (3x + 2)(4 – 5x)
= 12x + 8 – 15x2 – 10x
= –15x2 + 2x + 8
\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(
g
f
)(x)=
g(x)
f(x)
= \small{\dfrac{3x+2}{4-5x}}=
4−5x
3x+2
My answer is the neat listing of each of my results, clearly labelled as to which is which.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}
The regression equation which correctly models the data in this table is y = 1.49x - 107.5,
<h3>How to determine the regression equation?</h3>
From the table of data values, we have the following parameters:
∑x = 632
∑y = 404
∑x² = 80.142
∑xy = 51.448
Mathematically, the regression equation is represented by the following slope equation:
y = Bx + A
Next, we would determine A by using this expression:
A = (∑y·∑x² - ∑x·∑xy)/(n∑x² - (∑x)²)
A = (404×80,142 - 632×51,448)/(5×∑x² - (632)²)
A = (32,377,368 - 32,515136)/(5×80142 - 399,424)
A = -137,768/1286
A = 107.5
For B, we have:
B = (n∑xy· - ∑x·∑y)/(n∑x² - (∑x)²)
B = (5×51,448 - 632×404)/(5×∑x² - (632)²)
B = 1.49.
y = Bx + A
y = 1.49x - 107.5
Read more about regression equation here: brainly.com/question/28037520
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9 places should be moved towards left
here eight zeros after decimal point
7.2 × 10-9 = 0. 0000000072
Answer:
n = 120i + 310j + 60k
p = 29i + 18j + 21 k
Total cost = $10,320
Step-by-step explanation:
Let n and p represent the vectors for number of products and prices respectively.
Also, the coordinates i,j and k represent cashews, walnut and Brazil nut respectively.
The vector form of the total number of bags ordered and the cost are;
n = 120i + 310j + 60k
p = 29i + 18j + 21 k
We can obtain the total cost by obtaining the dot product of the two vectors.
Total cost = n.p = (120i + 310j + 60k).(29i + 18j + 21 k)
C = 120×29 + 310×18 + 60×21
C = $10,320
