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yanalaym [24]
4 years ago
6

How does the reaction of hydrogen and oxygen to produce energy in a fuel cell differ from their interaction during the direct co

mbustion of hydrogen and oxygen?
Chemistry
1 answer:
Nikolay [14]4 years ago
7 0
Need more information
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What do voltage-gated ion channels open in response to?.
Pavlova-9 [17]

Answer:Voltage-gated channels open (activate) in response to changes in membrane potential because the electric field acts on the channel to change its protein conformation (or state). It is voltage-gated sodium (Na+) channels that initiate action potentials and voltage-gated K+ channels that cause them to end.

3 0
3 years ago
A student tests a solid sample of a compound and determines that it does not conduct electric
Vitek1552 [10]

Answer:

A

Explanation:

because they are non polar so would not conduct electricity :)

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Eyes, nose, mouth would each be an example of a(n)
Masja [62]

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I think it is Organ

Explanation:

5 0
3 years ago
Calculate the vapor pressure of spherical water droplets of radius (a) 17 nm and (b) 2.0 μm surrounded by water vapor at 298 K.
Montano1993 [528]

Explanation:

Relation between pressure of water and its droplet is as follows.

           ln (\frac{p}{p_{o}}) = \frac{2 \gamma M}{r \rho RT}

where,   p = pressure of droplet

          p_{o} = water pressure in given temperature

          \gamma = 7.99 \times 10^{-3}

           M = Molecular Weight in Kg/Mol (0.018 for water)

            r = radius in meters

     \rho = density of water in Kg/m^{3} (1000 kg/m^{3})

           R = ideal gas constant (8.31)

           T = temperature in Kelvin

(a)   We will calculate the value of p as follows.

           p = e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}

              = e^{\frac{2 \times 0.07199 \times 0.018}{1.7 \times 10^{-8} \times 1000 \times 8.31 \times 298 K} \times 25.2

              = 26.8 torr

(b)  And, vapor pressure of spherical water droplets of radius 2.0 \mu m or 2 \times 10^{-6} m

             p = e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}

              = e^{\frac{2 \times 0.07199 \times 0.018}{2 \times 10^{-6} \times 1000 \times 8.31 \times 298 K} \times 25.2

              = 25.2 torr

7 0
4 years ago
If I have 0.75 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres, what is the volume of the gas
gladu [14]

Answer:

the volume is 20 just subtract

Explanation:

8 0
3 years ago
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