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3 years ago

How many valence electrons does nickel (Ni) have?

Chemistry

2 answers:

ValentinkaMS [17]3 years ago

8 0

It has 10 valence electrons

kumpel [21]3 years ago

7 0

Nickel has 10 valence electrons.

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Earth is unique because it is the _____.

astraxan [27]

Answer:

B. The only planet to support life.

Explanation:

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3 years ago

Read 2 more answers

Which of the following is the largest volume? 4.0 x 101 m3 3.8 x 107 cm3 3.8 x 105 dm3 3.8 x 108 mm3

fiasKO [112]

Answer : Option A) 4.0 X 101 $m^{3}$

Explanation : As per the measurement chart the greatest metric system is measured in meters.

So the rest values are given in the form of metric values which are obviously less than that of meters. values of centimeters, decimeter and millimeters are less than that of meters.

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3 years ago

A measurement must include both number and a ?

MatroZZZ [7]

Unit of measurement
ex: ft, in, etc.

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3 years ago

Uranium has an atomic weight of 238 amu.

shepuryov [24]

Answer:

U= 238g/mol

U2O5= 556g/mol

Explanation:

Since U= 238

O=16

U3O5= 2(238)+3(16)=556g/mol

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3 years ago

Sodium peroxide (Na2O2) is often used in self-contained breathing devices, such as those used in fire emergencies, because it re

Anastaziya [24]

Answer:

725.15 L

Explanation:

The balanced chemical equation for the reaction between Na₂O₂ and CO₂ is the following:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

From the stoichiometry of the reaction, 1 mol of Na₂O₂ reacts with 1 mol CO₂. So, the stoichiometric ratio is 1 mol Na₂O₂/1 CO₂.

Now, we convert the mass of reactants to moles by using the molecular weight (Mw) of each compound:

Mw (Na₂O₂) = (23 g/mol x 2) + (16 g/mol x 2) = 78 g/mol

moles Na₂O₂ = 96.7 g/(78 g/mol) = 1.24 mol Na₂O₂

Mw (CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

moles CO₂ = 0.0755 g/(44 g/mol) = 1.71 x 10⁻³ mol CO₂

Now, we calculate the number of moles of CO₂ we need to completely react with the mass of Na₂O₂ we have:

1.24 mol Na₂O₂ x 1 mol CO₂/1 mol Na₂O₂ = 1.24 mol CO₂

In 1 L of respired air we have 1.71 x 10⁻³ mol CO₂ (0.0755 g), so we need the following number of liters to have 1.24 mol of CO₂:

1.24 mol CO₂ x 1 L/1.71 x 10⁻³ mol CO₂ = 725.15 L

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3 years ago