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Ne4ueva [31]
3 years ago
8

Covalent bonds generally form when the bonded elements have a difference in electronegativity less than 1.5. Subtract the electr

onegativities for the following pairs of elements and predict whether they form a covalent bond.
Electronegativity difference of C and C:

ionic

covalent
Electronegativity difference of Mg and Cl:

ionic

covalent
Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0
Covalent and for mg cl ionic
velikii [3]3 years ago
4 0

Answer:

Electronegativity difference of C and C: 0.0

covalent

Electronegativity difference of Mg and Cl: 1.8

ionic

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The decomposition of copper(II) nitrate on heating is endothermic reaction. 2Cu(NO3)2(s) → 2C10(s) + 4NO2(g) + O2(g) Calculate t
Basile [38]

Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

2Cu(NO_3)_2(s)\rightarrow 2CuO(s) + 4NO_2(g) + O_2(g),\Delta H_{rxn}=?

We have :

Enthalpy changes of formation of following s:

\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol

\Delta H_{f,CuO}=-157.3 kJ/mol

\Delta H_{f,NO_2}= 33.2 kJ/mol

\Delta H_{f,O_2}= 0 kJ/mol (standard state)

\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]

The equation for the enthalpy change of the given reaction is:

\Delta H_{rxn} =

=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})

\Delta H_{rxn}=

(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)

\Delta H_{rxn}=424 kJ

The enthalpy change for the given reaction is 424 kJ.

6 0
4 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
This drawing shows a human body system.
White raven [17]

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the drawing  referred to in the question.

However, each option refers to a particular respiratory system and with the organs and the tissues mentioned here one can eventually identify which option is correct when the drawing is available.

A) The system described here is the cardiovascular system (or the circulatory system). This system involves the heart, blood vessels and the blood (which are what help in the transport of the materials mentioned in the question).

B) The system described here is the digestive system. This system involves the gastrointestinal tract and organs (that assist in the production/secretion or storage of chemicals that breakdown food into smaller pieces) such as the mouth, esophagus, stomach, small intestine, large intestine, rectum and the anus.

C) The system described here is the skeletal system. This system involves all the bones and joint in the body (the skeleton) which also helps in protecting organs in the body.

D) The system described here is the Endocrine system. This system involves several internal glands (such as the thyroid gland and the adrenal glands) in the body.

NOTE: Identify which organ and/or tissue is present in the diagram and use that to select the appropriate option from the description of each of the options provided above.

4 0
3 years ago
Read 2 more answers
Determine the a) energy (in eV) and b) wavelength (in cm) corresponding to blue light of frequency 670 THz
Lesechka [4]

Answer :

(a) The energy of blue light (in eV) is 2.77 eV

(b) The wavelength of blue light is 4\times 10^{-5}cm

Explanation:

The relation between the energy and frequency is:  

Energy=h\times Frequency

where,

h = Plank's constant = 6.626\times 10^{-34}J.s

Given :

Frequency = 670THz=670\times 10^{12}s^{-1}

Conversion used :

1THz=10^{12}Hz\\1Hz=1s^{-1}\\1THz=10^{12}s^{-1}

So,  

Energy=(6.626\times 10^{-34}J.s)\times (670\times 10^{12}s^{-1})

Energy=4.44\times 10^{-19}J

Also,  

1J=6.24\times 10^{18}eV

So,  

Energy=(4.44\times 10^{-19})\times (6.24\times 10^{18}eV)

Energy=2.77eV

The energy of blue light (in eV) is 2.77 eV

The relation between frequency and wavelength is shown below as:

Frequency=\frac{c}{Wavelength}

Where,

c = the speed of light = 3\times 10^8m/s

Frequency = 670\times 10^{12}s^{-1}

So, Wavelength is:

670\times 10^{12}s^{-1}=\frac{3\times 10^8m/s}{Wavelength}

Wavelength=\frac{3\times 10^8m/s}{670\times 10^{12}s^{-1}}=4\times 10^{-7}m=4\times 10^{-5}cm

Conversion used : 1m=100cm

The wavelength of blue light is 4\times 10^{-5}cm

7 0
4 years ago
How does a lithium cation compare to a lithium atom?
ExtremeBDS [4]
The correct answer is gonna be C) A lithium cation ion is smaller

A lithium cation has lost its valence electrons, which causes the remaining electrons to be pulled in stronger by the positive charge in the nucleus. As they get closer to the nucleus, the overall size of the atom is decreased.
6 0
3 years ago
Read 2 more answers
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