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Ne4ueva [31]
3 years ago
8

Covalent bonds generally form when the bonded elements have a difference in electronegativity less than 1.5. Subtract the electr

onegativities for the following pairs of elements and predict whether they form a covalent bond.
Electronegativity difference of C and C:

ionic

covalent
Electronegativity difference of Mg and Cl:

ionic

covalent
Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0
Covalent and for mg cl ionic
velikii [3]3 years ago
4 0

Answer:

Electronegativity difference of C and C: 0.0

covalent

Electronegativity difference of Mg and Cl: 1.8

ionic

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Arbon dioxide is dissolved in blood (ph 7.5) to form a mixture of carbonic acid and bicarbonate. Part a neglecting free co2, wha
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Answer : The fraction of carbonic acid present in the blood is 5.95%

Explanation :

The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.

The pH of a buffer is calculated using Henderson equation which is given below.

pH = pKa + log \frac{[Base]}{[Acid]}

We have been given,

pH = 7.5

pKa of carbonic acid = 6.3

Let us plug in the values in Henderson equation to find the ratio Base/Acid.

7.5 = 6.3 + log \frac{[base]}{[acid]}

1.2 = log \frac{[base]}{[acid]}

\frac{[Base]}{[Acid]} = 10^{1.2}

\frac{[Base]}{[Acid]} = 15.8

[Base] = 15.8 \times [Acid]

The total of mole fraction of acid and base is 1. Therefore we have,

[Acid] + [Base] = 1

But Base = 15.8 x [Acid]. Let us plug in this value in above equation.

[Acid] + 15.8 \times [Acid] = 1

16.8 [Acid] = 1

[Acid] = \frac{1}{16.8}

[Acid] = 0.0595

[Acid] = 0.0595 x 100 = 5.95 %

The fraction of carbonic acid present in the blood is 5.95%

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3 years ago
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