Answer:
26.110 grams of O2 produced.
Explanation:
Calculate the amount of moles in KClO3 by dividing the amount of grams given by the atomic weight of the substance.
To get the atomic weight: K = 39.098, Cl = 35.45, O = 15.999, and there are 3 molecules of Oxygen, so multiply 15.999 by three.
39.098 + 35.45 + (15.999 * 3) = 122.548.
66.7g / 122.548 atomic mass = 0.544 moles.
The ratio of moles of KClO3 to moles of O2 is 2 to 3.
=
Cross multiply to get 1.632 = 2y. Y = 0.816, meaning 0.816 moles of O2 will be produced.
Convert this into grams by multiplying by the atomic weight of O2 (15.999 * 2 = 31.998).
0.816 * 31.998 = 26.110 grams of O2 produced.
What’s the question cuz I’m confused lol
One-twelfth the mass of a carbon-12
Chemical reaction is any process that involves rearangent of the molecular or ionic structure of substances. each chemical reaction is characterised by an activation energy required for the reaction to occur ,for the change or rearrangement to take place
now fro combustion of fuel:we provide this energy by spark (heat pulse).now what about electrolysis?just the mode and manner of providing energy is different:instead of talking of activation energy,we talk of activation overpotential,both bring conceptually the same thing.heat energy is replaced by potential difference in rough terms.
so in short ,electrolysis is a chemical change ,just the mode of activation is different that thermally initiated chemical reactions