All categories

1 year ago

____________ use cleaning solutions that eventually become spent and must be disposed of properly.

Chemistry

1 answer:

Elanso [62]1 year ago

8 0

The answer is- Part washers use cleaning solutions that eventually become spent and must be disposed of properly.

Cleaning solutions: Cleaning solution is a liquid solvent or solution used to clean the working surfaces and the parts of a machine.

What type of cleaning solution is Part washers?

Parts washers are mechanical devices that are designed to be cleaned to remove debris, dirt, oil, paint, and other substances that could potentially contaminate parts to prepare them for assembly, packaging, or even painting.

They are basically used to clean parts to make them ready for functional use.

Cleaning solutions for washing used parts are considered a special waste because they can be hazardous waste and are waste from an industrial process.

Used solvents are almost always hazardous waste. Both solvent and aqueous parts washers produce a sludge that is usually hazardous because it contains toxic metals and solvents from the parts being cleaned.

Absorbents used to wipe parts after washing are also dangerous if they contain toxic metals in concentrations exceeding regulatory limits or listed hazardous solvents, and used oil may also contain hazardous waste.

Thus, these cleaning solutions must be disposed of properly.

To learn more about the cleaning solutions, visit:

brainly.com/question/19465733

#SPJ4

You might be interested in

Zac releases the air from a balloon. Which statement best describes what will happen to the air that was inside the balloon?

ad-work [718]

The correct answer is the last option. When <span>Zac releases the air from a balloon, it will expand to fill the room. It will not expand in the sense that molecules will be big but the molecules will be more spread out into the room and more air molecules will be present to fill the room.</span>

8 0

3 years ago

Read 2 more answers

3.8 liters of sulfur vapor, S8(g), at 921.4°C and 5.87 atm is burned in excess pure oxygen gas to give sulfur dioxide gas measur

lilavasa [31]

Answer:

116.5 g of SO₂ are formed

Explanation:

The reaction is:

S₈(g) + 8O₂(g) → 8SO₂ (g)

Let's identify the moles of sulfur vapor, by the Ideal Gases Law

We convert the 921.4°C to Absolute T° → 921.4°C + 273 = 1194.4 K

5.87 atm . 3.8L = n . 0.082 L.atm/mol.K . 1194.4K

(5.87 atm . 3.8L) / (0.082 L.atm/mol.K . 1194.4K) = n → 0.228 moles of S₈

Ratio is 1:8, 1 mol of sulfur vapor can produce 8 moles of dioxide

Then, 0.228 moles of S₈ must produce (0.228 . 8) /1 = 1.82 moles

We convert the moles to g → 1.82 moles . 64.06 g /1mol = 116.5 g

3 0

3 years ago

Read 2 more answers

As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,

Semenov [28]

Answer:

$1.32\times 10^{-3} mol/L$ is the solubility of nitrogen gas in a diver's blood.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{N_2}=K_H\times p_{liquid}$

where,

$K_H$ = Henry's constant = $6.26 \times 10^{-4}mol/L.atm$

$p_{N_2}$ = partial pressure of nitrogen

$p_{N_2}= P\times \chi_{N_2}$ (Raoult's law)

$=2.71 atm\times 0.78=2.1138 atm$

$C_{N_2}=6.26 \times 10^{-4}mol/L.atm\times 2.1138 atm$

$C_{N_2}=1.32\times 10^{-3} mol/L$

$1.32\times 10^{-3} mol/L$ is the solubility of nitrogen gas in a diver's blood.

3 0

3 years ago

Which phrase best discribes wave motion

kap26 [50]

Answer:

propagation of disturbances—that is, deviations from a state of rest or equilibrium—from place to place in a regular and organized way. Most familiar are surface waves on water, but both sound and light travel as wavelike disturbances, and the motion of all subatomic particles exhibits wavelike properties.

Explanation:

4 0

3 years ago

Oxidation number of sulphur in H2SO4

DochEvi [55]

Answer

let the oxidation of sulphur is x

2(+1)+x+4(-2)=0

+2+x-8=0

+2-8+x=0

-6+x=0

x=6

Explanation:

i hope this will help you:)

8 0

3 years ago