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Stells [14]
1 year ago
7

____________ use cleaning solutions that eventually become spent and must be disposed of properly.

Chemistry
1 answer:
Elanso [62]1 year ago
8 0

The answer is- Part washers use cleaning solutions that eventually become spent and must be disposed of properly.

Cleaning solutions: Cleaning solution is a liquid solvent or solution used to clean the working surfaces and the parts of a machine.

What type of cleaning solution is Part washers?

  • Parts washers are mechanical devices that are designed to be cleaned to remove debris, dirt, oil, paint, and other substances that could potentially contaminate parts to prepare them for assembly, packaging, or even painting.
  • They are basically used to clean parts to make them ready for functional use.
  • Cleaning solutions for washing used parts are considered a special waste because they can be hazardous waste and are waste from an industrial process.
  • Used solvents are almost always hazardous waste. Both solvent and aqueous parts washers produce a sludge that is usually hazardous because it contains toxic metals and solvents from the parts being cleaned.
  • Absorbents used to wipe parts after washing are also dangerous if they contain toxic metals in concentrations exceeding regulatory limits or listed hazardous solvents, and used oil may also contain hazardous waste.
  • Thus, these cleaning solutions must be disposed of properly.

To learn more about the cleaning solutions, visit:

brainly.com/question/19465733

#SPJ4

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Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s).
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Answer:

26.110 grams of O2 produced.

Explanation:

Calculate the amount of moles in KClO3 by dividing the amount of grams given by the atomic weight of the substance.

To get the atomic weight: K = 39.098, Cl = 35.45, O = 15.999, and there are 3 molecules of Oxygen, so multiply 15.999 by three.

39.098 + 35.45 + (15.999 * 3) = 122.548.

66.7g / 122.548 atomic mass = 0.544 moles.

The ratio of moles of KClO3 to moles of O2 is 2 to 3.

\frac{2}{3} = \frac{0.544}{y}

Cross multiply to get 1.632 = 2y. Y = 0.816, meaning 0.816 moles of O2 will be produced.

Convert this into grams by multiplying by the atomic weight of O2 (15.999 * 2 = 31.998).

0.816 * 31.998 = 26.110 grams of O2 produced.

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